MTG NEET Physics

Two particles execute S.H.M of same amplitude and frequency along the same straight line from same mean position. They pass one another without collision, when going in opposite direction, each time their displacement is half of their amplitude. The phase-difference between them is each time their displacement is half of their amplitude. The phase-difference between [...]

Two bodies performing S.H.M. have same amplitude and frequency. Their phases at a certain instant are as shown in the figure. The phase difference between them is Two bodies performing S.H.M. have same amplitude and frequency. Their phases at a certain instant are as shown in the figure. The phase difference between them is November [...]

The figure shows the circular motion of a particle of a reference particle to represent simple harmonic motion. The amplitude of SHM is The figure shows the circular motion of a particle of a reference particle to represent simple harmonic motion. The amplitude of SHM is November 8, 2020 Category: Chapter 11 - SHM , [...]

A particle executes simple harmonic motion between x = – A and x = + A .The time taken by it to go from O to A /2 is T1 and to go from A /2 to A is T 2. Then A particle executes simple harmonic motion between x = - A and x [...]

The amplitude of SHM. y=2(sin 5 pi t+sqrt(2)cos 5 pi t) is The amplitude of SHM. y=2(sin 5 pi t+sqrt(2)cos 5 pi t) is November 8, 2020 Category: Chapter 11 - SHM , MTG NEET Physics , Part 1 ,

A particle is subjected simultaneously to two SHM’s one along the x axis and the other along the y – axis. The two vibrations are in phase and have unequal amplitudes. The particles will execute. A particle is subjected simultaneously to two SHM's one along the x axis and the other along the y - [...]

Two simple harmonic motions are represented by y1=4sin(4πt+π/2) and y2=3cos(4πt). The resultant amplitude is Two simple harmonic motions are represented by y1=4sin(4πt+π/2) and y2=3cos(4πt). The resultant amplitude is November 8, 2020 Category: Chapter 11 - SHM , MTG NEET Physics , Part 1 ,

A particle executing simple harmonic motion has a period of 6 s. The time taken by the particle to move from the mean position to half the amplitude, starting from the mean position is November 8, 2020 Category: Chapter 11 - SHM , MTG NEET Physics , Part 1 ,

The amplitude of a damped oscillator becomes ( 3/ 1 )rd in 2s. If its amplitude after 6 s in n/1 times the original amplitude, the value of n is The amplitude of a damped oscillator becomes ( 3/ 1 )rd in 2s. If its amplitude after 6 s in n/1 times the original amplitude [...]

A particle of mass 200g is making SHM under the influence of a spring of force constant k=90 N/m and a damping constant b=40 g/s. calculate the time elapsed for the amplitude to drop to half its initial value. The amplitude of a damped oscillator becomes (4/1)rd in 4s. If its amplitude after 8 s [...]