JEE Mains Physics 2002-2019 Solved Video Solutions
A plane electromagnetic wave of frequency 50 MHz travels in free space along the positive x-direction. At a particular point is space and time, E→=6.3jˆV/m. The corresponding magnetic field Bˆ, at that point will be:
07
Jun
A plane electromagnetic wave of frequency 50 MHz travels in free space along the positive x-direction. At a particular point is space and time, E→=6.3jˆV/m. The corresponding magnetic field Bˆ, at that point will be: A plane electromagnetic wave of frequency 50 MHz travels in free space along the positive x-direction. At a particular point [...]
The electric field of a plane electromagnetic wave is given by E =E0i^cos(kz)cos(ωt) The corresponding magnetic field B is then given by :
07
Jun
The electric field of a plane electromagnetic wave is given by E =E0i^cos(kz)cos(ωt) The corresponding magnetic field B is then given by : The electric field of a plane electromagnetic wave is given by E =E0i^cos(kz)cos(ωt) The corresponding magnetic field B is then given by : June 7, 2021 Category: Chapter 15 - Electromagnetic Waves [...]
The magnetic field of a plane electromagnetic wave is given by: B=B0[cos(kz−ωt)]i+B1cos(kz+ωt)j where B0=3×10^−5T and B1=2×10^−6T. The rms value of the force experienced by a stationary charge Q=10^−4C at z=0 is close to:
07
Jun
The magnetic field of a plane electromagnetic wave is given by: B=B0[cos(kz−ωt)]i+B1cos(kz+ωt)j where B0=3×10^−5T and B1=2×10^−6T. The rms value of the force experienced by a stationary charge Q=10^−4C at z=0 is close to: Velocity of light is equal to June 7, 2021 Category: Chapter 15 - Electromagnetic Waves , JEE Mains Physics 2002-2019 Solved Video [...]
A plane electromagnetic wave travels in free space along the x-direction. The electric field component of the wave at a particular point of space and time is E=6Vm^−1 along y-direction. Its corresponding magnetic field component, B would be :
05
Jun
A plane electromagnetic wave travels in free space along the x-direction. The electric field component of the wave at a particular point of space and time is E=6Vm^−1 along y-direction. Its corresponding magnetic field component, B would be : Velocity of light is equal to June 5, 2021 Category: Chapter 15 - Electromagnetic Waves , [...]
Two vectors vector A and vector B are defined as vector A = ai and vector B = a(cosωti + sinωtj), where α is a constant and ω = π/6rad s–1. If |vector A + vector B| = √3|vector A – vector B| at time t = τ for the first time, the value of t, in seconds, is _____
11
Feb
Two vectors vector A and vector B are defined as vector A = ai and vector B = a(cosωti + sinωtj), where α is a constant and ω = π/6rad s–1. If |vector A + vector B| = √3|vector A – vector B| at time t = τ for the first time, the value of [...]
To find the distance d over which a signal can be seen clearly in foggy conditions, a railways engineer uses dimensional and assumes that the distance depends on the mass density p of the fog, intensity(power/area) S of the light from the signal and its frequency f. The engineer finds that d is proportional to S^1/n . the value of n is
10
Feb
To find the distance d over which a signal can be seen clearly in foggy conditions, a railways engineer uses dimensional and assumes that the distance depends on the mass density p of the fog, intensity(power/area) S of the light from the signal and its frequency f. The engineer finds that d is proportional to [...]
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a railways engineer uses dimensional and assumes that the distance depends on the mass density p of the fog ,
intensity(power/area) S of the light from the signal and its frequency f. The engineer finds that d is proportional to S^1/n . the value of n is ,
To find the distance d over which a signal can be seen clearly in foggy conditions ,
match the physical quantiesgiven in column 1with dimensions expressed in terms of mass ( M ), length ( L) , time (T) , And charge ( Q ) given in coloumn II and wire the correct answer against the matched quantity in a tabular form in your answer book
10
Feb
match the physical quantiesgiven in column 1with dimensions expressed in terms of mass ( M ), length ( L) , time (T) , And charge ( Q ) given in coloumn II and wire the correct answer against the matched quantity in a tabular form in your answer book And charge ( Q ) given [...]
Column-1 gives three physical quantities. Select the appropriate units for the choices given in column-II. Some of the physical quantities may have more than one choice.
10
Feb
Column-1 gives three physical quantities. Select the appropriate units for the choices given in column-II. Some of the physical quantities may have more than one choice. Column-1 gives three physical quantities. Select the appropriate units for the choices given in column-II. Some of the physical quantities may have more than one choice. February 10, 2021 [...]
The relation between [ E0] and [mew0] is
10
Feb
The relation between [ E0] and [mew0] is The relation between [ E0] and [mew0] is February 10, 2021 Category: Chapter 5 - Rotational Motion , JEE Mains Physics 2002-2019 Solved Video Solutions ,
The relation between [ E ] and [ B ] is (a) [E] =[B] [L] [T] (B) [E] =[B] [L]^-1 [T] (C) [E] =[B] [L] [T]^-1 (d) [E] =[B] [L]^-1 [T]^-1
10
Feb
The relation between [ E ] and [ B ] is (a) [E] =[B] [L] [T] (B) [E] =[B] [L]^-1 [T] (C) [E] =[B] [L] [T]^-1 (d) [E] =[B] [L]^-1 [T]^-1 The relation between [ E ] and [ B ] is (a) [E] =[B] [L] [T] (B) [E] =[B] [L]^-1 [T] (C) [E] =[B] [...]