JEE Mains Physics 2002-2019 Solved Video Solutions
Kα wavelength emitted by an atom of atomic number Z = 11 is λ. Find the atomic number for an atom that emits Kα radiation with wavelength 4λ
15
Sep
Kα wavelength emitted by an atom of atomic number Z = 11 is λ. Find the atomic number for an atom that emits Kα radiation with wavelength 4λ Kα wavelength emitted by an atom of atomic number Z = 11 is λ. Find the atomic number for an atom that emits Kα radiation with wavelength [...]
A photon collides with a stationary hydrogen atom in ground state inelastically. Energy of the colliding photon is 10.2 eV. After a time interval of the order of micro second another photon collides with same hydrogen atom inelastically with an energy of 15 eV. What will be observed by the detector ?
15
Sep
A photon collides with a stationary hydrogen atom in ground state inelastically. Energy of the colliding photon is 10.2 eV. After a time interval of the order of micro second another photon collides with same hydrogen atom inelastically with an energy of 15 eV. What will be observed by the detector ? Beta rays emitted [...]
The energy of a photon is equal to the kinetic energy of a proton. The energy of the photon is E. Let λ1 be the de-Broglie wavelength of the proton and λ2 be the wavelength of the photon. The ratio λ1/λ2 is proportional to
15
Sep
The energy of a photon is equal to the kinetic energy of a proton. The energy of the photon is E. Let λ1 be the de-Broglie wavelength of the proton and λ2 be the wavelength of the photon. The ratio λ1/λ2 is proportional to Beta rays emitted by a radioactive material are. September 15, 2021 [...]
After 280 days, the activity of a radioactive sample is 6000 dps. The activity reduces to 3000 dps after another 140 days. The initial activity of the sample in dps is
15
Sep
After 280 days, the activity of a radioactive sample is 6000 dps. The activity reduces to 3000 dps after another 140 days. The initial activity of the sample in dps is After 280 days the activity of a radioactive sample is 6000 dps. The activity reduces to 3000 dps after another 140 days. The initial [...]
The figure shows the variation of photocurrent with anode potential for a photosensitive surface for three different radiations. Let Ia, Ib and Ic be the intensities and fa,fb and fc be the frequencies for the curves a, b and c respectively, then
15
Sep
The figure shows the variation of photocurrent with anode potential for a photosensitive surface for three different radiations. Let Ia, Ib and Ic be the intensities and fa,fb and fc be the frequencies for the curves a, b and c respectively, then B and C respectively fb and fc be the frequencies for the curves [...]
A nucleus with mass number 220 initially at rest emits an α – particle. If the Q value of the reaction is 5.5 MeV, calculate the kinetic energy of α-particle.
15
Sep
A nucleus with mass number 220 initially at rest emits an α – particle. If the Q value of the reaction is 5.5 MeV, calculate the kinetic energy of α-particle. A nucleus with mass number 220 initially at rest emits an α - particle. If the Q value of the reaction is 5.5 MeV calculate [...]
The electric potential between a proton and an electron is given by V = V0 in r/r0,where r0 is a constant. Assuming Bohr’s model to be applicable, write variation of rn with n, Here, n being the principal quantum number.
15
Sep
The electric potential between a proton and an electron is given by V = V0 in r/r0,where r0 is a constant. Assuming Bohr’s model to be applicable, write variation of rn with n, Here, n being the principal quantum number. Here n being the principal quantum number ? The electric potential between a proton and [...]
If the atom 100Fm^257 follows the Bohr’s model and the radius of last orbit of 100Fm^257 is n times the Bohr radius, then find n
15
Sep
If the atom 100Fm^257 follows the Bohr’s model and the radius of last orbit of 100Fm^257 is n times the Bohr radius, then find n If the atom 100Fm^257 follows the Bohr's model and the radius of last orbit of 100Fm^257 is n times the Bohr radius then find n. September 15, 2021 Category: Chapter [...]
The potential difference applied to an X-ray tube is 5 kV and the current through it is 3.2 mA. Then the number of electrons striking the target per second is
15
Sep
The potential difference applied to an X-ray tube is 5 kV and the current through it is 3.2 mA. Then the number of electrons striking the target per second is The potential difference applied to an X-ray tube is 5 kV and the current through it is 3.2 mA. Then the number of electrons striking [...]
The half-life of 215 At is 100μs. The time taken for the radioactivity of sample of 215 At to decay to 1/16th of its initial value is
15
Sep
The half-life of 215 At is 100μs. The time taken for the radioactivity of sample of 215 At to decay to 1/16th of its initial value is The half-life of 215 At is 100μs. The time taken for the radioactivity of sample of 215 At to decay to 1/16th of its initial value is September [...]