JEE Mains Physics 2002-2019 Solved Video Solutions
A boy can throw a stone up to a maximum height of 10 m. The maximum horizontal distance that the boy can throw the same stone up to will be:
23
Oct
A boy can throw a stone up to a maximum height of 10 m. The maximum horizontal distance that the boy can throw the same stone up to will be: A boy can throw a stone up to a maximum height of 10 m. The maximum horizontal distance that the boy can throw the same [...]
A Particle move from the point (2.0iˆ+4.0jˆ)m, at t 0 , with an initial velocity (5.0iˆ+4.0iˆ)ms^−1. It is acted upon by a constant force which produces a constant acceleration (4.0iˆ+4.0jˆ)ms^−2. What is the distance of the particle from the origin at time 2 s?
23
Oct
A Particle move from the point (2.0iˆ+4.0jˆ)m, at t 0 , with an initial velocity (5.0iˆ+4.0iˆ)ms^−1. It is acted upon by a constant force which produces a constant acceleration (4.0iˆ+4.0jˆ)ms^−2. What is the distance of the particle from the origin at time 2 s? A Particle move from the point (2.0iˆ+4.0jˆ)m At t = 0 [...]
A particle is moving along a circular path with a constant speed 10ms^−1.What is the magnitude of the change in velocity of the particle ,when it moves through an angle of 60^∘ around the center of the circle ?
23
Oct
A particle is moving along a circular path with a constant speed 10ms^−1.What is the magnitude of the change in velocity of the particle ,when it moves through an angle of 60^∘ around the center of the circle ? A particle is moving along a circular path with a constant speed 10ms^−1.What is the magnitude [...]
A body is project at t= 0 with a velocity 10ms^−1 at an angle of 60^∘ with the horizontal .The radius of curvature of its trajectory at t=1s is R. Neglecting air resistance and taking acceleration due to gravity g=10ms^−2, the value of R is :
23
Oct
A body is project at t= 0 with a velocity 10ms^−1 at an angle of 60^∘ with the horizontal .The radius of curvature of its trajectory at t=1s is R. Neglecting air resistance and taking acceleration due to gravity g=10ms^−2, the value of R is : In the cube of side 'a' shown in the [...]
In the cube of side ‘a’ shown in the figure, the vector from the central point of the face ABOD to the central point of the face BEFO will be :
23
Oct
In the cube of side ‘a’ shown in the figure, the vector from the central point of the face ABOD to the central point of the face BEFO will be : In the cube of side 'a' shown in the figure the vector from the central point of the face ABOD to the central point [...]
Two guns A and B can fire bullets at speeds 1 km/s and 2 km/s respectively. From a point on a horizontal ground, they are fired in all possible directions. The ratio of maximum areas covered by the bullets on the ground fired by the two guns is
23
Oct
Two guns A and B can fire bullets at speeds 1 km/s and 2 km/s respectively. From a point on a horizontal ground, they are fired in all possible directions. The ratio of maximum areas covered by the bullets on the ground fired by the two guns is they are fired in all possible directions. [...]
In three dimensional system the position co-ordinates of a particle in motion are given below x=a cos wt y=a sinwt and z=awt The velocity of the particle will be
23
Oct
In three dimensional system the position co-ordinates of a particle in motion are given below x=a cos wt y=a sinwt and z=awt The velocity of the particle will be In three dimensional system the position co-ordinates of a particle in motion are given below x=a cos wt y=a sinwt and z=awt The velocity of the [...]
In a car race on straight road, car A takes a times t less than car B at the finish and passes finishing point with a speed ‘v’ more than that of car B. Both the car start from rest and travel with constant acceleration a1 and a2 respectively. Then ‘v’ is equal to
23
Oct
In a car race on straight road, car A takes a times t less than car B at the finish and passes finishing point with a speed ‘v’ more than that of car B. Both the car start from rest and travel with constant acceleration a1 and a2 respectively. Then ‘v’ is equal to find [...]
A particle is moving with velocity v= k (yi+xj),where k is constant. the general equation for its path is
23
Oct
A particle is moving with velocity v= k (yi+xj),where k is constant. the general equation for its path is A particle is moving with velocity v= k (yi+xj) where k is constant. the general equation for its path is October 23, 2020 Category: Chapter 2 - Kinematics , JEE Mains Physics 2002-2019 Solved Video Solutions [...]
The trajectory of a projectile near the surface of the earth is given as y = 2x – 9x^2 . If it were launched at an angle θ0 with speed v0 then g = 10 ms^–2
23
Oct
The trajectory of a projectile near the surface of the earth is given as y = 2x – 9x^2 . If it were launched at an angle θ0 with speed v0 then g = 10 ms^–2 The trajectory of a projectile near the surface of the earth is given as y = 2x – 9x^2 [...]