JEE Mains Physics 2002-2019 Solved Video Solutions
The amplitude of a damped oscillator decreases to 0.9 times its original magnitude is 5s. In another 10s it will decrease to α times its original magnitude, where α equals.
06
Nov
The amplitude of a damped oscillator decreases to 0.9 times its original magnitude is 5s. In another 10s it will decrease to α times its original magnitude, where α equals. The amplitude of a damped oscillator decreases to 0.9 times its original magnitude is 5s. In another 10s it will decrease to α times its [...]
A particle moves with simple harmonic motion in a straight line. In first τ s, after starting from rest, it travels a distance a, and in next τ s it travels 2a, in the same direction, then:
06
Nov
A particle moves with simple harmonic motion in a straight line. In first τ s, after starting from rest, it travels a distance a, and in next τ s it travels 2a, in the same direction, then: A particle moves with simple harmonic motion in a straight line. In first τ s after starting from [...]
The period of oscillation of a simple pendulum is T = 2 π L/g−−√.Measured of L is 20.0 cm known to 1 mm accuracy and time for 100 oscillations of the pendulum is found to be 90 s using a wrist watch of 1 s resolution. The accuracy in the determination of g?
06
Nov
The period of oscillation of a simple pendulum is T = 2 π L/g−−√.Measured of L is 20.0 cm known to 1 mm accuracy and time for 100 oscillations of the pendulum is found to be 90 s using a wrist watch of 1 s resolution. The accuracy in the determination of g? November 6, [...]
A uniform string of length 20 m is suspended from a rigid support. A short wave pulse is introduced at a lowest end. It starts moving up the string. The time taken to reach the support is: (take g=10 ms^−2 ).
06
Nov
A uniform string of length 20 m is suspended from a rigid support. A short wave pulse is introduced at a lowest end. It starts moving up the string. The time taken to reach the support is: (take g=10 ms^−2 ). November 6, 2020 Category: Chapter 10 - Oscillation and Waves , JEE Mains Physics [...]
A particle performs simple harmonic motion with amplitude A. Its speed is tripled at the instant that it is at a distance 3/2A from equilibrium position. The new amplitude of the motion is.
06
Nov
A particle performs simple harmonic motion with amplitude A. Its speed is tripled at the instant that it is at a distance 3/2A from equilibrium position. The new amplitude of the motion is. November 6, 2020 Category: Chapter 10 - Oscillation and Waves , JEE Mains Physics 2002-2019 Solved Video Solutions ,
A particle is executing simple harmonic motion with a time period T. At time t=0, it is at its position of equilibrium. The kinetic energy – time graph of the particle will look like :
06
Nov
A particle is executing simple harmonic motion with a time period T. At time t=0, it is at its position of equilibrium. The kinetic energy – time graph of the particle will look like : November 6, 2020 Category: Chapter 10 - Oscillation and Waves , JEE Mains Physics 2002-2019 Solved Video Solutions ,
A silver atom in a solid oscillates in SHM in a certain direction with a frequency of 10^12s^−1. What is the force constant of the bonds connecting one atom with the other? Molecular weight of silver 108 and Avogadro number =6.02 × 10^23 g mol^−1
06
Nov
A silver atom in a solid oscillates in SHM in a certain direction with a frequency of 10^12s^−1. What is the force constant of the bonds connecting one atom with the other? Molecular weight of silver 108 and Avogadro number =6.02 × 10^23 g mol^−1 November 6, 2020 Category: Chapter 10 - Oscillation and Waves [...]
A simple harmonic motion is represented by: y = 5 (sin 3πt+ 3–√ cos 3πt) cm The amplitude and time period of the motion are:
06
Nov
A simple harmonic motion is represented by: y = 5 (sin 3πt+ 3–√ cos 3πt) cm The amplitude and time period of the motion are: November 6, 2020 Category: Chapter 10 - Oscillation and Waves , JEE Mains Physics 2002-2019 Solved Video Solutions ,
A pendulum is executing simple harmonic motion and its maximum kinetic energy is K1. If the length of the pendulum is doubled and it performs simple harmonic motion with the same amplitude as in the first case, its maximum kinetic energy is K2. Then?
06
Nov
A pendulum is executing simple harmonic motion and its maximum kinetic energy is K1. If the length of the pendulum is doubled and it performs simple harmonic motion with the same amplitude as in the first case, its maximum kinetic energy is K2. Then? A particle executes simple harmonic motion with an amplitude of 5 [...]
A simple pendulum of length 1 m is oscillating with an angular frequency 10rad/s. The support of the down with a small angular frequency of 1rad/s and an amplitude of 10^−2m . The relative changes in the angular frequency of the pendulum is best given by.
06
Nov
A simple pendulum of length 1 m is oscillating with an angular frequency 10rad/s. The support of the down with a small angular frequency of 1rad/s and an amplitude of 10^−2m . The relative changes in the angular frequency of the pendulum is best given by. A particle executes simple harmonic motion with an amplitude [...]