JEE Mains Physics 2002-2019 Solved Video Solutions
Radiation com in g from transitions n = 2 to n = 1 of hydrogen atoms fall on He+ ions in n = 1 and n = 2 states. The possible transition of helium ions as they absorb energy from the radiation is :
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Nov
Radiation com in g from transitions n = 2 to n = 1 of hydrogen atoms fall on He+ ions in n = 1 and n = 2 states. The possible transition of helium ions as they absorb energy from the radiation is : Radiation com in g from transitions n = 2 to n [...]
An astronomical telescope has a large aperture to
18
Nov
An astronomical telescope has a large aperture to An astronomical telescope has a large aperture to November 18, 2020 Category: Chapter 16 - Optics , JEE Mains Physics 2002-2019 Solved Video Solutions ,
Wavelength of light used in an optical instrument are λ1 = 4000 A∘ and λ2 = 5000 A∘ then ratio of their respective resolving powers (corresponding to λ1 and λ2 ) is
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Nov
Wavelength of light used in an optical instrument are λ1 = 4000 A∘ and λ2 = 5000 A∘ then ratio of their respective resolving powers (corresponding to λ1 and λ2 ) is Wavelength of light used in an optical instrument are λ1 = 4000 A∘ and λ2 = 5000 A∘ then ratio of their respective [...]
To demonstrate the phenomenon of interference we require two sources which emit radiation of
18
Nov
To demonstrate the phenomenon of interference we require two sources which emit radiation of To demonstrate the phenomenon of interference we require two sources which emit radiation of November 18, 2020 Category: Chapter 16 - Optics , JEE Mains Physics 2002-2019 Solved Video Solutions ,
The maximum number of possible interference maxima for slit-separation equal to twice the wavelength in Young’s double-slit experiment, is
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Nov
The maximum number of possible interference maxima for slit-separation equal to twice the wavelength in Young’s double-slit experiment, is is The maximum number of possible interference maxima for slit-separation equal to twice the wavelength in Young's double-slit experiment November 18, 2020 Category: Chapter 16 - Optics , JEE Mains Physics 2002-2019 Solved Video Solutions ,
The angle of incidence at which reflected light is totally polarised for reflection from air to glass (refractive index n) is
18
Nov
The angle of incidence at which reflected light is totally polarised for reflection from air to glass (refractive index n) is The angle of incidence at which reflected light is totally polarised for reflection from air to glass (refractive index n) is November 18, 2020 Category: Chapter 16 - Optics , JEE Mains Physics 2002-2019 [...]
When an unpolarized light of intensity I0 is incident on a polarizing sheet, the intensity of the light which does not get transmitted is :
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Nov
When an unpolarized light of intensity I0 is incident on a polarizing sheet, the intensity of the light which does not get transmitted is : the intensity of the light which does not get transmitted is When an unpolarized light of intensity I0 is incident on a polarizing sheet November 18, 2020 Category: Chapter 16 [...]
Two point white dots are 1 mm apart on a black paper. They are viewed by eye of pupil diameter 3mm. Approximately, what is the maximum distance at which these dots can be resolved by the eye ? [Take wavelength of light =500nm]
18
Nov
Two point white dots are 1 mm apart on a black paper. They are viewed by eye of pupil diameter 3mm. Approximately, what is the maximum distance at which these dots can be resolved by the eye ? [Take wavelength of light =500nm] Two point white dots are 1 mm apart on a black paper. [...]
A Young’s double slit experiment uses a monochromatic source. The shape of the interference fringes formed on a screen is :
18
Nov
A Young’s double slit experiment uses a monochromatic source. The shape of the interference fringes formed on a screen is : A Young’s double slit experiment uses a monochromatic source. The shape of the interference fringes formed on a screen is : November 18, 2020 Category: Chapter 16 - Optics , JEE Mains Physics 2002-2019 [...]
In a Young’s double slit experiment the intensity at a point where the path difference is 6/λ (λ being the wavelength of the light used) is I. if I0 denotes the maximum intensity, then I/I0 is equal to
18
Nov
In a Young’s double slit experiment the intensity at a point where the path difference is 6/λ (λ being the wavelength of the light used) is I. if I0 denotes the maximum intensity, then I/I0 is equal to In a Young's double slit experiment the intensity at a point where the path difference is 6/λ [...]