Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions)
A body is performing simple harmonic motion with amplitude a and time period T. Variation of its acceleration (f) with time (t) is shown in the given figure. If at time t, velocity of the body is v,
30
Oct
A body is performing simple harmonic motion with amplitude a and time period T. Variation of its acceleration (f) with time (t) is shown in the given figure. If at time t, velocity of the body is v, A body is performing simple harmonic motion with amplitude a and time period T. Variation of its [...]
A cylindrical container having area of cross-section equal to 4A, contains a non-viscous liquid of density 2 rho. A cylindrical block of wood having cross sectional area A and length L
30
Oct
A cylindrical container having area of cross-section equal to 4A, contains a non-viscous liquid of density 2 rho. A cylindrical block of wood having cross sectional area A and length L A cylindrical container having area of cross-section equal to 4A contains a non-viscous liquid of density 2 rho. A cylindrical block of wood having [...]
A cylinder of mass m and cross sectional area A floating in the liquid of density rho hangs from a rigid support P by an ideal spring of stiffness k. (1) Find the depth of immersion of
30
Oct
A cylinder of mass m and cross sectional area A floating in the liquid of density rho hangs from a rigid support P by an ideal spring of stiffness k. (1) Find the depth of immersion of A cylinder of mass m and cross sectional area A floating in the liquid of density rho hangs [...]
A smooth tube in the form of a semicircle of radius R is kept vertical. A non-viscous liquid is in equilibrium subtending an angle 2 theta at the centre C of the circle. Find the angular
30
Oct
A smooth tube in the form of a semicircle of radius R is kept vertical. A non-viscous liquid is in equilibrium subtending an angle 2 theta at the centre C of the circle. Find the angular A smooth tube in the form of a semicircle of radius R is kept vertical. A non-viscous liquid is [...]
Find the amplitude and phase of the vibrations x = A cos omega t + A/2 cos (omega t + pie/2) + A/4 cos (omega t + pie) + A/8 cos (omega t + 3 pie/2)
30
Oct
Find the amplitude and phase of the vibrations x = A cos omega t + A/2 cos (omega t + pie/2) + A/4 cos (omega t + pie) + A/8 cos (omega t + 3 pie/2) Find the amplitude and phase of the vibrations x = A cos omega t + A/2 cos (omega t [...]
If two SHMs are represented by y1 = 10 sin (4 pit t + pie/2) and y2 = 5 (sin 2 pie t + root 8 cos 2 pie t), compare their amplitudes.
30
Oct
If two SHMs are represented by y1 = 10 sin (4 pit t + pie/2) and y2 = 5 (sin 2 pie t + root 8 cos 2 pie t), compare their amplitudes. compare their amplitudes. If two SHMs are represented by y1 = 10 sin (4 pit t + pie/2) and y2 = 5 [...]
If the displacement of a moving point at any time is given by an equation of the form y(t) = a cos omega t + b sin omega t, show that the motion is simple harmonic. If a = 3 m
30
Oct
If the displacement of a moving point at any time is given by an equation of the form y(t) = a cos omega t + b sin omega t, show that the motion is simple harmonic. If a = 3 m If the displacement of a moving point at any time is given by an [...]
A particle is subjected to two simple harmonic motions: x1 = A1 sin omega t and x2 = A2 sin (omega t + pie / 3). Find (a) the displacement at t = 0, (b) the maximum speed of the particle
30
Oct
A particle is subjected to two simple harmonic motions: x1 = A1 sin omega t and x2 = A2 sin (omega t + pie / 3). Find (a) the displacement at t = 0, (b) the maximum speed of the particle (b) the maximum speed of the particle A particle is subjected to two simple [...]
x1 = 3 sin omega t; x2 = 4 cos omega t Find (a) amplitude of resultant SHM, (b) equation of the resultant SHM.
30
Oct
x1 = 3 sin omega t; x2 = 4 cos omega t Find (a) amplitude of resultant SHM, (b) equation of the resultant SHM. (b) equation of the resultant SHM. x1 = 3 sin omega t; x2 = 4 cos omega t Find (a) amplitude of resultant SHM October 30, 2020 Category: Uncategorised (JEE Advanced [...]
Given that x1 = 5 sin omega t x2 = 5 sin (omega t + 53) x3 = -10 cos omega t Find amplitude of resultant SHM.
30
Oct
Given that x1 = 5 sin omega t x2 = 5 sin (omega t + 53) x3 = -10 cos omega t Find amplitude of resultant SHM. Given that x1 = 5 sin omega t x2 = 5 sin (omega t + 53) x3 = -10 cos omega t Find amplitude of resultant SHM. October [...]