Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions)
Calculate equivalent resistance between A and B of the circuit shown in figure.
10
Nov
Calculate equivalent resistance between A and B of the circuit shown in figure. Calculate equivalent resistance between A and B of the circuit shown in figure. November 10, 2020 Category: Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) ,
Which of the following group of elements elements eliminates electron easily (a) N, P, As (b) O, S, Se (c) Li, Na, K (d) Cl, Ba, I
10
Nov
Which of the following group of elements elements eliminates electron easily (a) N, P, As (b) O, S, Se (c) Li, Na, K (d) Cl, Ba, I As (b) O Ba I K (d) Cl Na p S Se (c) Li Which of the following group of elements elements eliminates electron easily (a) N November [...]
If each of the resistance n the shown network is R, then what is the between A and B.
10
Nov
If each of the resistance n the shown network is R, then what is the between A and B. If each of the resistance n the shown network is R then what is the between A and B. November 10, 2020 Category: Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) ,
Elements A and B with their respective electronic configurations 3d10 4s1 and 4d10 5s1 in their outermost shell, are (a) Both non-metals (b) Both coinage metals (c) A is a non-metal
10
Nov
Elements A and B with their respective electronic configurations 3d10 4s1 and 4d10 5s1 in their outermost shell, are (a) Both non-metals (b) Both coinage metals (c) A is a non-metal are (a) Both non-metals (b) Both coinage metals (c) A is a non-metal Elements A and B with their respective electronic configurations 3d10 4s1 [...]
A hemispherical network of radius a is made by using a conducting wire of resistance per unit length r. Find the equivalent resistance across OP.
10
Nov
A hemispherical network of radius a is made by using a conducting wire of resistance per unit length r. Find the equivalent resistance across OP. A hemispherical network of radius a is made by using a conducting wire of resistance per unit length r. Find the equivalent resistance across OP. November 10, 2020 Category: Uncategorised [...]
3 and 6 electrons are present in the outermost orbit of A and B respectively. The chemical formula of its compound will be
10
Nov
3 and 6 electrons are present in the outermost orbit of A and B respectively. The chemical formula of its compound will be 3 and 6 electrons are present in the outermost orbit of A and B respectively. The chemical formula of its compound will be November 10, 2020 Category: Uncategorised (JEE Advanced Physics by [...]
The stable bivalency of Pb and trivalency of Bi is (a) Due to d contraction in Pb and Bi is (b) Due to relativistic contraction of the 6 s orbitals of Pb and Bi, leading to inert pair effect
10
Nov
The stable bivalency of Pb and trivalency of Bi is (a) Due to d contraction in Pb and Bi is (b) Due to relativistic contraction of the 6 s orbitals of Pb and Bi, leading to inert pair effect leading to inert pair effect The stable bivalency of Pb and trivalency of Bi is (a) [...]
In a periodic table the basic character of oxides (a) Increases form left to right and decreases from top to bottom (b) Decreases from right to left and increases from top to bottom
10
Nov
In a periodic table the basic character of oxides (a) Increases form left to right and decreases from top to bottom (b) Decreases from right to left and increases from top to bottom In a periodic table the basic character of oxides (a) Increases form left to right and decreases from top to bottom (b) [...]
Fluorine, chlorine, bromine and iodine are placed in the same group (17) of the periodic table, because (a) They are non-metals (b) They are electronegative
10
Nov
Fluorine, chlorine, bromine and iodine are placed in the same group (17) of the periodic table, because (a) They are non-metals (b) They are electronegative because (a) They are non-metals (b) They are electronegative bromine and iodine are placed in the same group (17) of the periodic table chlorine Fluorine November 10, 2020 Category: Uncategorised [...]
Beryllium and aluminium exhibit many properties which are similar. But, the two elements differ in (a) Forming covalent halides (b) Forming polymeric hydrides
10
Nov
Beryllium and aluminium exhibit many properties which are similar. But, the two elements differ in (a) Forming covalent halides (b) Forming polymeric hydrides Beryllium and aluminium exhibit many properties which are similar. But the two elements differ in (a) Forming covalent halides (b) Forming polymeric hydrides November 10, 2020 Category: Uncategorised (JEE Advanced Physics by [...]