Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions)
The method not used in metallurgy to refine the impure metal is (a) Mond’s process (b) Van-Arkel process (c) Amalgamation process
12
Nov
The method not used in metallurgy to refine the impure metal is (a) Mond’s process (b) Van-Arkel process (c) Amalgamation process The method not used in metallurgy to refine the impure metal is (a) Mond's process (b) Van-Arkel process (c) Amalgamation process November 12, 2020 Category: Uncategorised (JEE Advanced Physics by BM Sharma + GMP [...]
In an infinite network of resistances, each resistance of value R = 2 ohm , are arranged as shown in the figure. Find the equivalent resistance between A and B ( in ohm ).
12
Nov
In an infinite network of resistances, each resistance of value R = 2 ohm , are arranged as shown in the figure. Find the equivalent resistance between A and B ( in ohm ). are arranged as shown in the figure. Find the equivalent resistance between A and B ( in ohm ). each resistance [...]
In the circuit shown in figure,find the steady state charge in 6 muF capacitor ( in muC).
12
Nov
In the circuit shown in figure,find the steady state charge in 6 muF capacitor ( in muC). find the steady state charge in 6 muF capacitor ( in muC). In the circuit shown in Figure November 12, 2020 Category: Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) ,
In the given circuit, each reistance is r = 18.75 ohm. The current ( in A ) in the resistance connected across A and B is ‘ ….. ‘A.
12
Nov
In the given circuit, each reistance is r = 18.75 ohm. The current ( in A ) in the resistance connected across A and B is ‘ ….. ‘A. each reistance is r = 18.75 ohm. The current ( in A ) in the resistance connected across A and B is ' ..... 'A. In [...]
Which method of purification is represented by the equation Ti + 2I2 to TiI4 to Ti + 2I2
12
Nov
Which method of purification is represented by the equation Ti + 2I2 to TiI4 to Ti + 2I2 Which method of purification is represented by the equation Ti + 2I2 to TiI4 to Ti + 2I2 November 12, 2020 Category: Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) ,
Assertion : Leaching is a process of reduction. Reason : Leaching involves treatment of the ore with a suitable reagent so as to make it soluble while impurities remains insoluble.
12
Nov
Assertion : Leaching is a process of reduction. Reason : Leaching involves treatment of the ore with a suitable reagent so as to make it soluble while impurities remains insoluble. Assertion : Leaching is a process of reduction. Reason : Leaching involves treatment of the ore with a suitable reagent so as to make it [...]
To obtain chromium from chromic oxide (Cr2O3), the method used is (a) Alumino-thermic process (b) Electrolytic reduction (c) Carbon reduction
12
Nov
To obtain chromium from chromic oxide (Cr2O3), the method used is (a) Alumino-thermic process (b) Electrolytic reduction (c) Carbon reduction the method used is (a) Alumino-thermic process (b) Electrolytic reduction (c) Carbon reduction To obtain chromium from chromic oxide (Cr2O3) November 12, 2020 Category: Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) ,
Iron is obtained on a large scale from Fe2O3 by (a) Reduction with Al (b) Reduction with CO (c) Reduction with H2
12
Nov
Iron is obtained on a large scale from Fe2O3 by (a) Reduction with Al (b) Reduction with CO (c) Reduction with H2 Iron is obtained on a large scale from Fe2O3 by (a) Reduction with Al (b) Reduction with CO (c) Reduction with H2 November 12, 2020 Category: Uncategorised (JEE Advanced Physics by BM Sharma [...]
In aluminium extraction by the Baeyer’s process, alumina is extracted from bauxite by sodium hydroxide at high temperatures and pressures
12
Nov
In aluminium extraction by the Baeyer’s process, alumina is extracted from bauxite by sodium hydroxide at high temperatures and pressures alumina is extracted from bauxite by sodium hydroxide at high temperatures and pressures In aluminium extraction by the Baeyer's process November 12, 2020 Category: Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) ,
The potential difference Va- Vb for the circuit shown in figure is -(22/x) V. Find the value of x.
12
Nov
The potential difference Va- Vb for the circuit shown in figure is -(22/x) V. Find the value of x. The potential difference Va- Vb for the circuit shown in figure is -(22/x) V. Find the value of x. November 12, 2020 Category: Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) ,