Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions)
As a result of change in the magnetic flux linked to the closed loop shown in the fig, an e.m.f. V volt is induced in the loop. The work done (joule) in taking a charge Q coulomb once along the loop is
07
Dec
As a result of change in the magnetic flux linked to the closed loop shown in the fig, an e.m.f. V volt is induced in the loop. The work done (joule) in taking a charge Q coulomb once along the loop is an e.m.f. V volt is induced in the loop. The work done (joule) [...]
A circular disc of radius 0.2m is placed in a uniform magnetic field of induction 1/π(Wb/m^2) in such a way that its axis makes an angle of 60∘ with B. The magnetic flux linked with the disc is
07
Dec
A circular disc of radius 0.2m is placed in a uniform magnetic field of induction 1/π(Wb/m^2) in such a way that its axis makes an angle of 60∘ with B. The magnetic flux linked with the disc is A circular disc of radius 0.2m is placed in a uniform magnetic field of induction 1/π(Wb/m^2) in [...]
A cell has an emf 1.5V. When connected across an external resistance of 2Ω, the terminal potential difference falls to 1.0V. The internal resistance of the cell is:
07
Dec
A cell has an emf 1.5V. When connected across an external resistance of 2Ω, the terminal potential difference falls to 1.0V. The internal resistance of the cell is: A cell has an emf 1.5V. When connected across an external resistance of 2Ω the terminal potential difference falls to 1.0V. The internal resistance of the cell [...]
Two identical batteries, each of e.m.f. 2 volt and internal resistance 1.0 ohm are available to produce heat in a resistance by passing a current through it. The maximum power that can be developed across R using these batteries is.
07
Dec
Two identical batteries, each of e.m.f. 2 volt and internal resistance 1.0 ohm are available to produce heat in a resistance by passing a current through it. The maximum power that can be developed across R using these batteries is. Faraday's laws are consequence of conservation of Two identical batteries December 7, 2020 Category: Uncategorised [...]
The current flowing through 3 ohm resistor is 0.8 ampere, then potential drop across the 4 ohm resistor is :
07
Dec
The current flowing through 3 ohm resistor is 0.8 ampere, then potential drop across the 4 ohm resistor is : The current flowing through 3 ohm resistor is 0.8 ampere then potential drop across the 4 ohm resistor is : December 7, 2020 Category: Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) ,
The volume of 0.1 M H2SO4 that is needed to completely neutralise 40 ml of 0.2 M NaOH is
07
Dec
The volume of 0.1 M H2SO4 that is needed to completely neutralise 40 ml of 0.2 M NaOH is The volume of 0.1 M H2SO4 that is needed to completely neutralise 40 ml of 0.2 M NaOH is December 7, 2020 Category: Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) ,
A solution containing Na2CO3 and NaOH requires 300 ml of 0.1 N HCl using phenolphthalein as an indicator. Methyl orange is then added to above titrated solution when a further
07
Dec
A solution containing Na2CO3 and NaOH requires 300 ml of 0.1 N HCl using phenolphthalein as an indicator. Methyl orange is then added to above titrated solution when a further A solution containing Na2CO3 and NaOH requires 300 ml of 0.1 N HCl using phenolphthalein as an indicator. Methyl orange is then added to above [...]
0.16 gm of a dibasic acid require 25 ml of decinormal NaOH solution for complete neutralization. The molecular weight of the acid is
07
Dec
0.16 gm of a dibasic acid require 25 ml of decinormal NaOH solution for complete neutralization. The molecular weight of the acid is 0.16 gm of a dibasic acid require 25 ml of decinormal NaOH solution for complete neutralization. The molecular weight of the acid is December 7, 2020 Category: Uncategorised (JEE Advanced Physics by [...]
Volume of 0.1 M H2SO4 required to neutralize 30 ml of 0.2 N NaOH is (a) 30 ml (b) 15 ml
07
Dec
Volume of 0.1 M H2SO4 required to neutralize 30 ml of 0.2 N NaOH is (a) 30 ml (b) 15 ml Volume of 0.1 M H2SO4 required to neutralize 30 ml of 0.2 N NaOH is (a) 30 ml (b) 15 ml December 7, 2020 Category: Uncategorised (JEE Advanced Physics by BM Sharma + GMP [...]
The bond angle and dipole moment of water respectively are (a) 109.5degree, 1.84 D (b) 107.5 degree ,1.56 D (c) 104.5 degree , 1.84 D (d) 102.5 degree , 1.56 D
07
Dec
The bond angle and dipole moment of water respectively are (a) 109.5degree, 1.84 D (b) 107.5 degree ,1.56 D (c) 104.5 degree , 1.84 D (d) 102.5 degree , 1.56 D 1.56 D 1.56 D (c) 104.5 degree 1.84 D (b) 107.5 degree 1.84 D (d) 102.5 degree The bond angle and dipole moment of [...]