Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions)
The paramagnetic behaviour of B2 is due to the presence of (a) 2 unpaired electrons in pie b MO (b) 2 unpaired electrons in pie * MO
08
Dec
The paramagnetic behaviour of B2 is due to the presence of (a) 2 unpaired electrons in pie b MO (b) 2 unpaired electrons in pie * MO The paramagnetic behaviour of B2 is due to the presence of (a) 2 unpaired electrons in pie b MO (b) 2 unpaired electrons in pie * MO December [...]
Heterolytic bond association energy of alkyl halides follow the sequence (a) R-F > R-Cl > R-Br > R-I
08
Dec
Heterolytic bond association energy of alkyl halides follow the sequence (a) R-F > R-Cl > R-Br > R-I Heterolytic bond association energy of alkyl halides follow the sequence (a) R-F > R-Cl > R-Br > R-I December 8, 2020 Category: Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) ,
The bond order in O2^- ion is (a) 2 (b) 1 (c) 2.5 (d) 1.5
08
Dec
The bond order in O2^- ion is (a) 2 (b) 1 (c) 2.5 (d) 1.5 The bond order in O2^- ion is (a) 2 (b) 1 (c) 2.5 (d) 1.5 December 8, 2020 Category: Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) ,
Consider the following compounds (a) Chloroethene B. Benzene C. 1,3 butadiene D. 1, 3, 5 hexatriene All the carbon atoms are sp2 hybridised in
08
Dec
Consider the following compounds (a) Chloroethene B. Benzene C. 1,3 butadiene D. 1, 3, 5 hexatriene All the carbon atoms are sp2 hybridised in 3 butadiene D. 1 3% 5 hexatriene All the carbon atoms are sp2 hybridised in Consider the following compounds (a) Chloroethene B. Benzene C. 1 December 8, 2020 Category: Uncategorised (JEE [...]
Number of pie electrons present in naphthalene is (a) 4 (b) 6 (c) 10 (d) 14
08
Dec
Number of pie electrons present in naphthalene is (a) 4 (b) 6 (c) 10 (d) 14 Number of pie electrons present in naphthalene is (a) 4 (b) 6 (c) 10 (d) 14 December 8, 2020 Category: Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) ,
Example of sp2 hybridization is (a) CH3 + (b) CH3 (c) C2H5 + (d) C2H5
08
Dec
Example of sp2 hybridization is (a) CH3 + (b) CH3 (c) C2H5 + (d) C2H5 Example of sp2 hybridization is (a) CH3 + (b) CH3 (c) C2H5 + (d) C2H5 December 8, 2020 Category: Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) ,
Toluene has (a) 6 sigma and 3 pie bond (b) 9 sigma and 3 pie bond (c) 9 sigma and 6 pie bond
08
Dec
Toluene has (a) 6 sigma and 3 pie bond (b) 9 sigma and 3 pie bond (c) 9 sigma and 6 pie bond Toluene has (a) 6 sigma and 3 pie bond (b) 9 sigma and 3 pie bond (c) 9 sigma and 6 pie bond December 8, 2020 Category: Uncategorised (JEE Advanced Physics by [...]
Hybridization of 1 and 2 carbon atoms in CH2 = C = CH2 (a) sp, sp (b) sp2, sp2 (c) sp2, sp
08
Dec
Hybridization of 1 and 2 carbon atoms in CH2 = C = CH2 (a) sp, sp (b) sp2, sp2 (c) sp2, sp Hybridization of 1 and 2 carbon atoms in CH2 = C = CH2 (a) sp sp sp (b) sp2 sp2 (c) sp2 December 8, 2020 Category: Uncategorised (JEE Advanced Physics by BM Sharma [...]
The correct statement with regard to H^+2 and H^−2 is (a) Both H+2 and H−2 do not exist (b) H−2 is more stable than H+2 (c) H−2 is more stable than H+2 (d) Both H+2 and H−2 are equally stable
08
Dec
The correct statement with regard to H^+2 and H^−2 is (a) Both H+2 and H−2 do not exist (b) H−2 is more stable than H+2 (c) H−2 is more stable than H+2 (d) Both H+2 and H−2 are equally stable The correct statement with regard to H^+2 and H^−2 is (a) Both H+2 and H−2 [...]
In which of the following molecules, all atoms are coplanar
08
Dec
In which of the following molecules, all atoms are coplanar all atoms are coplanar In which of the following molecules December 8, 2020 Category: Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) ,