Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions)
A mass of 10 kg is suspended vertically by a rope from the roof. When a horizontal force is applied on the rope at some point, the rope deviated at an angle of 45 o at the roof point. If the suspended mass is at equilibrium, the magnitude of the force applied is (g=10 ms 2)
14
Feb
A mass of 10 kg is suspended vertically by a rope from the roof. When a horizontal force is applied on the rope at some point, the rope deviated at an angle of 45 o at the roof point. If the suspended mass is at equilibrium, the magnitude of the force applied is (g=10 ms [...]
A bullet of mass 20 g has an initial speed of 1 ms^−1 , just before it starts penetrating a mud wall of thickness 20cm. if the wall offers a mean resistance of 2.5×10 −2 N, the speed of the bullet after emerging from the other side of the wall is close to
14
Feb
A bullet of mass 20 g has an initial speed of 1 ms^−1 , just before it starts penetrating a mud wall of thickness 20cm. if the wall offers a mean resistance of 2.5×10 −2 N, the speed of the bullet after emerging from the other side of the wall is close to A bullet [...]
Disintegration constant for a radioactive substance is 0.58 /hr . Its half – life period (a) 8.2 hr (b) 5.2 hr (c) 1.2 hr (d) 2.4 hr
14
Feb
Disintegration constant for a radioactive substance is 0.58 /hr . Its half – life period (a) 8.2 hr (b) 5.2 hr (c) 1.2 hr (d) 2.4 hr Disintegration constant for a radioactive substance is 0.58 /hr . Its half - life period (a) 8.2 hr (b) 5.2 hr (c) 1.2 hr (d) 2.4 hr February [...]
The half – life of a radioactive element is 10 hours . How much will be left after 4 hours in 1 g atom sample
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Feb
The half – life of a radioactive element is 10 hours . How much will be left after 4 hours in 1 g atom sample The half - life of a radioactive element is 10 hours . How much will be left after 4 hours in 1 g atom sample February 14, 2021 Category: Uncategorised [...]
The half – life of the radio element 83 Bi^210 in 5 days . Starting with 20 g of this isotope , the amount remaining after 15 days is
14
Feb
The half – life of the radio element 83 Bi^210 in 5 days . Starting with 20 g of this isotope , the amount remaining after 15 days is the amount remaining after 15 days is The half - life of the radio element 83 Bi^210 in 5 days . Starting with 20 g of [...]
Radium has atomic weight 226 and a half – life of 1600 years . The number of disintegration produced per second from 1 g are
14
Feb
Radium has atomic weight 226 and a half – life of 1600 years . The number of disintegration produced per second from 1 g are Radium has atomic weight 226 and a half - life of 1600 years . The number of disintegration produced per second from 1 g are February 14, 2021 Category: Uncategorised [...]
The amout of 53 I ^128 ( t 1/2 = 25 minutes ) left after 50 minutes will be (a) 1/2 (b) 1/3 (c) 1/4 (d) Nothing
14
Feb
The amout of 53 I ^128 ( t 1/2 = 25 minutes ) left after 50 minutes will be (a) 1/2 (b) 1/3 (c) 1/4 (d) Nothing The amout of 53 I ^128 ( t 1/2 = 25 minutes ) left after 50 minutes will be (a) 1/2 (b) 1/3 (c) 1/4 (d) Nothing February [...]
Wooden article and freshly cut tree are 7.6 and 15.2 /min /g of carbon ( t1/2 = 5760 years ) respectively . The age of teh artifact is
14
Feb
Wooden article and freshly cut tree are 7.6 and 15.2 /min /g of carbon ( t1/2 = 5760 years ) respectively . The age of teh artifact is Wooden article and freshly cut tree are 7.6 and 15.2 /min /g of carbon ( t1/2 = 5760 years ) respectively . The age of teh artifact [...]
The appreciable readioactivity of uranium minerals is mainly due to (a) An uranium isotope of mass number 235 (b) A thorium isotope of mass number 232 (c) Actinium (d) Radium
14
Feb
The appreciable readioactivity of uranium minerals is mainly due to (a) An uranium isotope of mass number 235 (b) A thorium isotope of mass number 232 (c) Actinium (d) Radium The appreciable readioactivity of uranium minerals is mainly due to (a) An uranium isotope of mass number 235 (b) A thorium isotope of mass number [...]
For the fission raection 92 U^235 + 0n^1 gives 56 Ba^140 + yE^x + 2 0n^1 The value of x and y will be
14
Feb
For the fission raection 92 U^235 + 0n^1 gives 56 Ba^140 + yE^x + 2 0n^1 The value of x and y will be For the fission raection 92 U^235 + 0n^1 gives 56 Ba^140 + yE^x + 2 0n^1 The value of x and y will be February 14, 2021 Category: Uncategorised (JEE Advanced [...]