Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions)
A ball is projected from a point in a horizontal plane so as to strike a vertical wall at right angle and after rebounding from the wall and once from the horizontal plane it returns to the point of projection. Find coefficient of restitution (e) for the two collisions, assuming it to be same for both collision. Find the value of 1/e.
23
Aug
A ball is projected from a point in a horizontal plane so as to strike a vertical wall at right angle and after rebounding from the wall and once from the horizontal plane it returns to the point of projection. Find coefficient of restitution (e) for the two collisions, assuming it to be same for [...]
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(i) find the velocity of the ball just after the impact. (ii) determine the impulsive tension(i.e impulse) in the string at the instant of collision. ,
An elastic ball of mass 'm' is suspended from a fixed point by an inextensible string. A small particle of same mass m ,
moving downwards at an angle of 37^(@) with the vertical lits the ball directly with the velocity v_(0). If the coefficient of restitution is 4//5 ,
An elastic ball of mass ‘m’ is suspended from a fixed point by an inextensible string. A small particle of same mass m, moving downwards at an angle of 37^(@) with the vertical lits the ball directly with the velocity v_(0). If the coefficient of restitution is 4//5, (i) find the velocity of the ball just after the impact. (ii) determine the impulsive tension(i.e impulse) in the string at the instant of collision.
23
Aug
An elastic ball of mass ‘m’ is suspended from a fixed point by an inextensible string. A small particle of same mass m, moving downwards at an angle of 37^(@) with the vertical lits the ball directly with the velocity v_(0). If the coefficient of restitution is 4//5, (i) find the velocity of the ball [...]
Tags:
(i) find the velocity of the ball just after the impact. (ii) determine the impulsive tension(i.e impulse) in the string at the instant of collision. ,
An elastic ball of mass 'm' is suspended from a fixed point by an inextensible string. A small particle of same mass m ,
moving downwards at an angle of 37^(@) with the vertical lits the ball directly with the velocity v_(0). If the coefficient of restitution is 4//5 ,
PQR is a wedge fixed to the floor. Two blocks A & B of equal mass m=1kg is placed on either side of wedge connected through a string passing over the pulley P. Initially PB=PA. Another block C of mass m=1kg moving with a velocity 10m//s collides inelasically with A. All the surfaces are smooth and pulley & string are massless. (a) What should be the minimum length of the string AB so that block A does not hit the pulley ? (b) What is the loss in meechanical energy from the instant C hits A to the instant when B starts moving upward ? (g=10m//s^(2))
23
Aug
PQR is a wedge fixed to the floor. Two blocks A & B of equal mass m=1kg is placed on either side of wedge connected through a string passing over the pulley P. Initially PB=PA. Another block C of mass m=1kg moving with a velocity 10m//s collides inelasically with A. All the surfaces are smooth [...]
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A carpet of unit mass an unit length is laid on the floor. One end of the carpet is bent back and then pulled backwards with constants. Unit velocity ,
just above the part of the carpet which is still at rest on the floor. Find the speed of the centre of mass of the moving part. What is the minimum force needed to pull the moving part ? ,
A carpet of unit mass an unit length is laid on the floor. One end of the carpet is bent back and then pulled backwards with constants. Unit velocity, just above the part of the carpet which is still at rest on the floor. Find the speed of the centre of mass of the moving part. What is the minimum force needed to pull the moving part ?
23
Aug
A carpet of unit mass an unit length is laid on the floor. One end of the carpet is bent back and then pulled backwards with constants. Unit velocity, just above the part of the carpet which is still at rest on the floor. Find the speed of the centre of mass of the moving [...]
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A carpet of unit mass an unit length is laid on the floor. One end of the carpet is bent back and then pulled backwards with constants. Unit velocity ,
just above the part of the carpet which is still at rest on the floor. Find the speed of the centre of mass of the moving part. What is the minimum force needed to pull the moving part ? ,
A carpet of unit mass an unit length is laid on the floor. One end of the carpet is bent back and then pulled backwards with constants. Unit velocity, just above the part of the carpet which is still at rest on the floor. Find the speed of the centre of mass of the moving part. What is the minimum force needed to pull the moving part ?
23
Aug
A carpet of unit mass an unit length is laid on the floor. One end of the carpet is bent back and then pulled backwards with constants. Unit velocity, just above the part of the carpet which is still at rest on the floor. Find the speed of the centre of mass of the moving [...]
Tags:
A carpet of unit mass an unit length is laid on the floor. One end of the carpet is bent back and then pulled backwards with constants. Unit velocity ,
just above the part of the carpet which is still at rest on the floor. Find the speed of the centre of mass of the moving part. What is the minimum force needed to pull the moving part ? ,
The graph between force between the atoms [F(x)] vs x will be
23
Aug
The graph between force between the atoms [F(x)] vs x will be The graph between force between the atoms [F(x)] vs x will be August 23, 2020 Category: Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) ,
The dissociation energy of a molecule is the energy required to
23
Aug
The dissociation energy of a molecule is the energy required to The dissociation energy of a molecule is the energy required to August 23, 2020 Category: Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) ,
The graph between potential energy vs x will be
23
Aug
The graph between potential energy vs x will be The graph between potential energy vs x will be August 23, 2020 Category: Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) ,
A force shown in the F-x graph is applied to a 2kg block horizontal as shown in figure. The change in kinetic energy is
23
Aug
A force shown in the F-x graph is applied to a 2kg block horizontal as shown in figure. The change in kinetic energy is A force shown in the F-x graph is applied to a 2kg block horizontal as shown in figure. The change in kinetic energy is August 23, 2020 Category: Uncategorised (JEE Advanced [...]
A projectile is fired with some velocity making certain angle with the horizontal. Which of the following graphs is the best representation for the kinetic energy of a projectile (KE) versus its horizontal displacement(x)?
23
Aug
A projectile is fired with some velocity making certain angle with the horizontal. Which of the following graphs is the best representation for the kinetic energy of a projectile (KE) versus its horizontal displacement(x)? A particle of mass m slides on a frictionless surface ABCD starting from rest as shown in Figure. The part BCD [...]