Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions)
A police jeep, approaching a right-angled intersection from the north, is chasing a speeding car that has turned the corner and is now moving straight east. When the jeep is 0.6 km north of the intersection and the car is 0.8 km to the east, the police determine with radar that the distance between them and the car is increasing at 20 km/h^-1. If the jeep is moving at 60 km h^-1 at the instant of measurement, what is the speed of the car?
26
Aug
A police jeep, approaching a right-angled intersection from the north, is chasing a speeding car that has turned the corner and is now moving straight east. When the jeep is 0.6 km north of the intersection and the car is 0.8 km to the east, the police determine with radar that the distance between them [...]
Tags:
A police jeep ,
approaching a right-angled intersection from the north ,
is chasing a speeding car that has turned the corner and is now moving straight east. When the jeep is 0.6km north of the intersection and the car is 0.8km to the east ,
the police determine with radar that the distance between them and the car is increasing at 20kmh^-1. If the jeep is moving at 60kmh^-1 at the instant of measurement ,
what is the speed of the car? ,
In the previous problem, if the particle occupies a position x=7m at t=1s, then obtain an expression for the instantaneous displacement of the particle.
26
Aug
In the previous problem, if the particle occupies a position x=7m at t=1s, then obtain an expression for the instantaneous displacement of the particle. if the particle occupies a position x=7m at t=1s In the previous problem then obtain an expression for the instantaneous displacement of the particle. August 26, 2020 Category: Uncategorised (JEE Advanced [...]
A particle moves with a constant acceleration a=2 ms −2 along a straight line. If its moves with an initial velocity of 5 ms −1 , then obtain an expression for its instantaneous velocity.
26
Aug
A particle moves with a constant acceleration a=2 ms −2 along a straight line. If its moves with an initial velocity of 5 ms −1 , then obtain an expression for its instantaneous velocity. A particle moves with a constant acceleration a=2 ms −2 along a straight line. If its moves with an initial velocity [...]
Let the instantaneous velocity of a rocket just after launching, be given by the expression v = 2t + 3t^2 (where v is in m/s and t is in seconds). Find out the distance travelled by the rocket from t=2 s to t=3 s.
26
Aug
Let the instantaneous velocity of a rocket just after launching, be given by the expression v = 2t + 3t^2 (where v is in m/s and t is in seconds). Find out the distance travelled by the rocket from t=2 s to t=3 s. be given by the expression v = 2t + 3t^2 (where [...]
A particle starts moving and its displace-ment after t seconds is given in meter by the relation x=5+4t+3t^2. Calculate the magnitude of its a. Initial velocity b. Velocity at t=3s c. Acceleration
26
Aug
A particle starts moving and its displace-ment after t seconds is given in meter by the relation x=5+4t+3t^2. Calculate the magnitude of its a. Initial velocity b. Velocity at t=3s c. Acceleration A particle starts moving and its displace-ment after t seconds is given in meter by the relation x=5+4t+3t^2. Calculate the magnitude of its [...]
Sita is driving along a staight highway in her car. At time t = 0, when Sita is moving at 10 ms^-1 in the positive x-direction, she passes a signpost at x = 50 m. Here acceleration is a function of time: a = 2.0 ms^-2 – (1/10 ms^-3)t a. Derive expressions for her velocity and position as functions of time. b. At what time is her velocity greatest? c. What is the maximum velocity? d. Where is the car when it reaches the maximum velocity?
26
Aug
Sita is driving along a staight highway in her car. At time t = 0, when Sita is moving at 10 ms^-1 in the positive x-direction, she passes a signpost at x = 50 m. Here acceleration is a function of time: a = 2.0 ms^-2 – (1/10 ms^-3)t a. Derive expressions for her velocity [...]
At t = 0, a body starts from origin with some initial velocity. The displacement x(m) of the body varies with time t(s) as x = – (2/3)t^2 + 16t + 2. Find the initial velocity of the body and also find how long does the body take to come to rest? What is the acceleration of the body when it comes to rest?
26
Aug
At t = 0, a body starts from origin with some initial velocity. The displacement x(m) of the body varies with time t(s) as x = – (2/3)t^2 + 16t + 2. Find the initial velocity of the body and also find how long does the body take to come to rest? What is the [...]
Calculate the area enclosed under the curve f(x)=x^2 between the limits x=2 and x=3 (figure)
26
Aug
Calculate the area enclosed under the curve f(x)=x^2 between the limits x=2 and x=3 (figure) Calculate the area enclosed under the curve f(x)=x^2 between the limits x=2 and x=3 (figure) August 26, 2020 Category: Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) ,
Evaluate int(2zdz)/(root3(z^2+1))
26
Aug
Evaluate int(2zdz)/(root3(z^2+1)) Evaluate int(2zdz)/(root3(z^2+1)) August 26, 2020 Category: Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) ,
Evaluate int sqrt (1 + y^2).2y dy
26
Aug
Evaluate int sqrt (1 + y^2).2y dy Evaluate intsqrt(1+y^(2)).2ydy August 26, 2020 Category: Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) ,