Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions)
Match the statements of column I and column II
15
Sep
Match the statements of column I and column II Match the statements of column I and column II September 15, 2020 Category: Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) ,
Which of the following statements is/are correct ( may have more thanm one option correct).
15
Sep
Which of the following statements is/are correct ( may have more thanm one option correct). Which of the following statements is/are correct ( may have more thanm one option correct). September 15, 2020 Category: Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) ,
An atomic power nuclear reactor can deliver 300 MW. The energy released due to fission of each nucleus of uranium atom U^238 is 170 Me V. The number of uranium atoms fissioned per hour will be
15
Sep
An atomic power nuclear reactor can deliver 300 MW. The energy released due to fission of each nucleus of uranium atom U^238 is 170 Me V. The number of uranium atoms fissioned per hour will be An atomic power nuclear reactor can deliver 300 MW. The energy released due to fission of each nucleus of [...]
Fission of nuclei is possible because the binding energy per nucleon in them
15
Sep
Fission of nuclei is possible because the binding energy per nucleon in them Fission of nuclei is possible because the binding energy per nucleon in them September 15, 2020 Category: Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) ,
The nuclear reaction .2H+.2H→.4He (mass of deuteron =2.0141 a.m.u and mass of He = 4.0024 a.m.u) is
15
Sep
The nuclear reaction .2H+.2H→.4He (mass of deuteron =2.0141 a.m.u and mass of He = 4.0024 a.m.u) is The nuclear reaction .2H+.2H→.4He (mass of deuteron =2.0141 a.m.u and mass of He = 4.0024 a.m.u) is September 15, 2020 Category: Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) ,
The energy liberated on complete fission of 1 kg of 92 U^235 is ( Assume 200 Me V energy is liberated on fission of 1 nucleus)
15
Sep
The energy liberated on complete fission of 1 kg of 92 U^235 is ( Assume 200 Me V energy is liberated on fission of 1 nucleus) The energy liberated on complete fission of 1 kg of 92 U^235 is ( Assume 200 Me V energy is liberated on fission of 1 nucleus) September 15, 2020 [...]
The binding energy per nucleon of deuterium and helium atom is 1.1 Me V and 7.0 Me V. If two deuterium nuclei fuse to form helium atom, the energy released is
15
Sep
The binding energy per nucleon of deuterium and helium atom is 1.1 Me V and 7.0 Me V. If two deuterium nuclei fuse to form helium atom, the energy released is The binding energy per nucleon of deuterium and helium atom is 1.1 Me V and 7.0 Me V. If two deuterium nuclei fuse to [...]
To generate power of 3.2 megawatt , the number of fissions of U^235 per minute is ( Energy released per fission = 200 Me V, 1 eV = 1.6 X 10^-19 J )
15
Sep
To generate power of 3.2 megawatt , the number of fissions of U^235 per minute is ( Energy released per fission = 200 Me V, 1 eV = 1.6 X 10^-19 J ) 1 eV = 1.6 X 10^-19 J ) the number of fissions of U^235 per minute is ( Energy released per fission [...]
If the energy released in the fission of one nucleus is 200 Me V. Then the number of nuclei required per second in a power plant of 16 KW will be
15
Sep
If the energy released in the fission of one nucleus is 200 Me V. Then the number of nuclei required per second in a power plant of 16 KW will be If the energy released in the fission of one nucleus is 200 Me V. Then the number of nuclei required per second in a [...]
If 200 Me v energy is released in the fission of a single U^235, the number of fission required per second to produce 1 kilowatt power shall be ( Given 1 eV = 1.6 x 10^-19 J )
15
Sep
If 200 Me v energy is released in the fission of a single U^235, the number of fission required per second to produce 1 kilowatt power shall be ( Given 1 eV = 1.6 x 10^-19 J ) If 200 Me v energy is released in the fission of a single U^235 the number of [...]