Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions)
In Fig. what should be the speed of the charged particle so that it cannot collide with the upper wall? Also, find the coordinates of the point where the particle strikes the lower plate in the limiting case of velocity.
13
Oct
In Fig. what should be the speed of the charged particle so that it cannot collide with the upper wall? Also, find the coordinates of the point where the particle strikes the lower plate in the limiting case of velocity. find the coordinates of the point where the particle strikes the lower plate in the [...]
A particle with charge 6.40 × 10^−19 C travels in a circular orbit with radius 4.68 mm due to the force exerted on it by a magnetic field of magnitude 1.65 T and perpendicular to the orbit. a. What is the magnitude of the linear momentum P of the particle? b. What is the magnitude of the angular momentum L of the particle?
13
Oct
A particle with charge 6.40 × 10^−19 C travels in a circular orbit with radius 4.68 mm due to the force exerted on it by a magnetic field of magnitude 1.65 T and perpendicular to the orbit. a. What is the magnitude of the linear momentum P of the particle? b. What is the magnitude [...]
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and has a magnitude of 2.25 × 10^−5 T (a) In what direction are the electrons deflected by this field component? (b) What is the acceleration of an electron in part (a)? ,
The electrons in the beam of a television tube have a kinetic energy of 4.5 ×10^−15 J Initially ,
the electrons move horizontally from west to east. The vertical component of the earth's magnetic field points down ,
toward the surface of the earth ,
The electrons in the beam of a television tube have a kinetic energy of 4.5 ×10^−15 J Initially, the electrons move horizontally from west to east. The vertical component of the earth’s magnetic field points down, toward the surface of the earth, and has a magnitude of 2.25 × 10^−5 T (a) In what direction are the electrons deflected by this field component? (b) What is the acceleration of an electron in part (a)?
13
Oct
The electrons in the beam of a television tube have a kinetic energy of 4.5 ×10^−15 J Initially, the electrons move horizontally from west to east. The vertical component of the earth’s magnetic field points down, toward the surface of the earth, and has a magnitude of 2.25 × 10^−5 T (a) In what direction [...]
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and has a magnitude of 2.25 × 10^−5 T (a) In what direction are the electrons deflected by this field component? (b) What is the acceleration of an electron in part (a)? ,
The electrons in the beam of a television tube have a kinetic energy of 4.5 ×10^−15 J Initially ,
the electrons move horizontally from west to east. The vertical component of the earth's magnetic field points down ,
toward the surface of the earth ,
The drawing shows a parallel plate capacitor that is moving with a speed of 20 m/s through a 5.0-T magnetic field. The velocity is perpendicular to the magnetic field. The electric field within the capacitor has a value of 200 N/C, and each plate has an area of 5.0 x 10^-4 m^2. What is the magnetic force (magnitude and direction) exerted on the positive plate of the capacitor?
13
Oct
The drawing shows a parallel plate capacitor that is moving with a speed of 20 m/s through a 5.0-T magnetic field. The velocity is perpendicular to the magnetic field. The electric field within the capacitor has a value of 200 N/C, and each plate has an area of 5.0 x 10^-4 m^2. What is the [...]
Two charged particles move in the same direction with respect to the same magnetic field. particle 1 travels two times faster than particle 2. however, each particle experiences a magnetic force of the same magnitude. find the ratio q1 / q2 of the magnitudes of the charges.
13
Oct
Two charged particles move in the same direction with respect to the same magnetic field. particle 1 travels two times faster than particle 2. however, each particle experiences a magnetic force of the same magnitude. find the ratio q1 / q2 of the magnitudes of the charges. each particle experiences a magnetic force of the [...]
An electron moves through a uniform magnetic field given by B = Bxiˆ+(3Bx) jˆ. At a particular instant, the electron has the velocity v = ( 2.0iˆ+4.0jˆ) m/s and the magnetic force acting on its is ( 6.4×10^−19 N ) kˆ Find Bx.
13
Oct
An electron moves through a uniform magnetic field given by B = Bxiˆ+(3Bx) jˆ. At a particular instant, the electron has the velocity v = ( 2.0iˆ+4.0jˆ) m/s and the magnetic force acting on its is ( 6.4×10^−19 N ) kˆ Find Bx. An electron moves through a uniform magnetic field given by B = [...]
A particle of charge q > 0 is moving at speed v in the +z direction through a region of uniform magnetic field. The magnetic force on the particle F = F0 (3iˆ+4jˆ), where F0 is a positive constant. (a) Determine the components Bx, By and Bz or at least as many of the three components as is possible from the information given. (b) If it is given in addition that the magnetic field has magnitude 6 F0 qv , determine the magnitude of Bz.
13
Oct
A particle of charge q > 0 is moving at speed v in the +z direction through a region of uniform magnetic field. The magnetic force on the particle F = F0 (3iˆ+4jˆ), where F0 is a positive constant. (a) Determine the components Bx, By and Bz or at least as many of the three [...]
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A particle of charge q > 0 is moving at speed v in the +z direction through a region of uniform magnetic field. The magnetic force on the particle F = F0 (3iˆ+4jˆ) ,
By and Bz or at least as many of the three components as is possible from the information given. (b) If it is given in addition that the magnetic field has magnitude 6 F0 qv ,
determine the magnitude of Bz. ,
where F0 is a positive constant. (a) Determine the components Bx ,
A charged particle of mass 10 g and charge 50 muC, moves through a uniform magnetic field , in a region where the free- fall acceleration is -10 jm/s^2. Thje velocity of the particle is constant 20 i km/s, which is perpendiucular to the magnetic field. What , then, is the magnetic field?
13
Oct
A charged particle of mass 10 g and charge 50 muC, moves through a uniform magnetic field , in a region where the free- fall acceleration is -10 jm/s^2. Thje velocity of the particle is constant 20 i km/s, which is perpendiucular to the magnetic field. What , then, is the magnetic field? A charged [...]
A particle with charge 7.00 μC is moving with velocity v→=−( 4 × 10^3 m/s)jˆ. The magnetic force on the particle is measured to be F→=+(8.4 × 10^−2 N)iˆ−(5.60 × 10^−2 N)kˆ. a. Calculate all the components of the magnetic field you can from this information. b. Are there components of the magnetic field that cannot be determined by measurement of the force? Explain. c. Calculate the scalar product B→.F→. What is the angle between B→andF→?
13
Oct
A particle with charge 7.00 μC is moving with velocity v→=−( 4 × 10^3 m/s)jˆ. The magnetic force on the particle is measured to be F→=+(8.4 × 10^−2 N)iˆ−(5.60 × 10^−2 N)kˆ. a. Calculate all the components of the magnetic field you can from this information. b. Are there components of the magnetic field that [...]
When a proton has a velocity v→= (2iˆ+3jˆ) × 10^6 m/s, it experiences a force F→=−( 1.28 ×10^−13 kˆ) N. When its velocity is along the z-axis, it experiences a force along the x-axis. What is the magnetic field?
13
Oct
When a proton has a velocity v→= (2iˆ+3jˆ) × 10^6 m/s, it experiences a force F→=−( 1.28 ×10^−13 kˆ) N. When its velocity is along the z-axis, it experiences a force along the x-axis. What is the magnetic field? it experiences a force along the x-axis. What is the magnetic field? it experiences a force [...]