Chapter 7 – Equilibrium
Sahay Sir > Question Answers > JEE Adv and Mains Chemistry 41 Years Solved Video Solutions 1979 - 2019 > Chemistry > Chapter 7 - Equilibrium
What is the molar solubility of Fe(OH)2 (Ksp = 8.0 10^-16) at pH 13.0?
17
Nov
What is the molar solubility of Fe(OH)2 (Ksp = 8.0 10^-16) at pH 13.0? What is the molar solubility of Fe(OH)2 (Ksp = 8.0 10^-16) at pH 13.0? November 17, 2020 Category: Chapter 6 - Ionic Equilibrium (Level 1 and Level 2) , Chapter 7 - Equilibrium , N Awasthi Physical Chemistry ,
What is the pH of a saturated solution of Cu(OH)2? (Ksp=2.6×10^−19)
17
Nov
What is the pH of a saturated solution of Cu(OH)2? (Ksp=2.6×10^−19) What is the pH of a saturated solution of Cu(OH)2? (Ksp=2.6×10^−19) November 17, 2020 Category: Chapter 6 - Ionic Equilibrium (Level 1 and Level 2) , Chapter 7 - Equilibrium , N Awasthi Physical Chemistry ,
The solubility product of AgCl is 10^−10 M^2. The minimum volume ( in m^3) of water required to dissolve 14.35 mg of AgCl is approximately :
17
Nov
The solubility product of AgCl is 10^−10 M^2. The minimum volume ( in m^3) of water required to dissolve 14.35 mg of AgCl is approximately : The solubility product of AgCl is 10^−10 M^2. The minimum volume ( in m^3) of water required to dissolve 14.35 mg of AgCl is approximately : November 17, 2020 [...]
What is the molarity of F− in a saturated solution of InF3?(Ksp=7.9×10^−10)
17
Nov
What is the molarity of F− in a saturated solution of InF3?(Ksp=7.9×10^−10) What is the molarity of F− in a saturated solution of InF3?(Ksp=7.9×10^−10) November 17, 2020 Category: Chapter 6 - Ionic Equilibrium (Level 1 and Level 2) , Chapter 7 - Equilibrium , N Awasthi Physical Chemistry ,
What is the molarity of F− ions in a saturated solution of BaF2? (Ksp=1.0×10^−6)
17
Nov
What is the molarity of F− ions in a saturated solution of BaF2? (Ksp=1.0×10^−6) What is the molarity of F− ions in a saturated solution of BaF2? (Ksp=1.0×10^−6) November 17, 2020 Category: Chapter 6 - Ionic Equilibrium (Level 1 and Level 2) , Chapter 7 - Equilibrium , N Awasthi Physical Chemistry ,
How many grams of MgC2O4 (formula mass =122) will dissolve in 1.5 L of water? (Ksp=8.1×10^−5)
17
Nov
How many grams of MgC2O4 (formula mass =122) will dissolve in 1.5 L of water? (Ksp=8.1×10^−5) How many grams of MgC2O4 (formula mass =122) will dissolve in 1.5 L of water? (Ksp=8.1×10^−5) November 17, 2020 Category: Chapter 6 - Ionic Equilibrium (Level 1 and Level 2) , Chapter 7 - Equilibrium , N Awasthi Physical [...]
The solubility of PbF2 (formula mass =245) is 0.46 g/L. What is the solubility product?
17
Nov
The solubility of PbF2 (formula mass =245) is 0.46 g/L. What is the solubility product? The solubility of PbF2 (formula mass =245) is 0.46 g/L. What is the solubility product? November 17, 2020 Category: Chapter 6 - Ionic Equilibrium (Level 1 and Level 2) , Chapter 7 - Equilibrium , N Awasthi Physical Chemistry ,
The solubility of AgBrO3 (formula mass=236) is 0.0072 g in 1000 mL. What is the Ksp?
17
Nov
The solubility of AgBrO3 (formula mass=236) is 0.0072 g in 1000 mL. What is the Ksp? The solubility of AgBrO3 (formula mass=236) is 0.0072 g in 1000 mL. What is the Ksp? November 17, 2020 Category: Chapter 6 - Ionic Equilibrium (Level 1 and Level 2) , Chapter 7 - Equilibrium , N Awasthi Physical [...]
The solubility of Ba3 (AsO4 )2 (formula mass = 690) is 6.9×10^−2 g/100 mL. What is the Ksp ?
17
Nov
The solubility of Ba3 (AsO4 )2 (formula mass = 690) is 6.9×10^−2 g/100 mL. What is the Ksp ? The solubility of Ba3 (AsO4 )2 (formula mass = 690) is 6.9×10^−2 g/100 mL. What is the Ksp ? November 17, 2020 Category: Chapter 6 - Ionic Equilibrium (Level 1 and Level 2) , Chapter 7 [...]
If Ksp for HgSO4 is 6.4×10^−5, then solubility of this substance in mole per m^3 is :
17
Nov
If Ksp for HgSO4 is 6.4×10^−5, then solubility of this substance in mole per m^3 is : If Ksp for HgSO4 is 6.4×10^−5 then solubility of this substance in mole per m^3 is : November 17, 2020 Category: Chapter 6 - Ionic Equilibrium (Level 1 and Level 2) , Chapter 7 - Equilibrium , N [...]