Chapter 13 – Simple Harmonic Motion
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A body is executing SHM, At a displacement x, its potential energy is E1 and at a displacement y, its potential energy is E2. Find its potential energy E at displacement ( x + y) is
30
Oct
A body is executing SHM, At a displacement x, its potential energy is E1 and at a displacement y, its potential energy is E2. Find its potential energy E at displacement ( x + y) is A body is executing SHM At a displacement x its potential energy is E1 and at a displacement y [...]
The kinetic energy and potential energy of a particle executing SHM will be equal when displacement (amplitude = a) is
30
Oct
The kinetic energy and potential energy of a particle executing SHM will be equal when displacement (amplitude = a) is The kinetic energy and potential energy of a particle executing SHM will be equal when displacement (amplitude = a) is October 30, 2020 Category: Cengage NEET by C.P Singh , Chapter 13 - Simple Harmonic [...]
The potential energy of a particle with displacement X is U(X). The motion is simple harmonic, when (K is a positive constant)
30
Oct
The potential energy of a particle with displacement X is U(X). The motion is simple harmonic, when (K is a positive constant) The potential energy of a particle with displacement X is U(X). The motion is simple harmonic when (K is a positive constant) October 30, 2020 Category: Cengage NEET by C.P Singh , Chapter [...]
A particle executes SHM with a time period of 16s. At time t=2s, the particle crosses the mean position while at t=4s, its velocity is 4 ms^−1. The amplitude of motion in metre is?
30
Oct
A particle executes SHM with a time period of 16s. At time t=2s, the particle crosses the mean position while at t=4s, its velocity is 4 ms^−1. The amplitude of motion in metre is? A particle executes SHM with a time period of 16s. At time t=2s its velocity is 4 ms^−1. The amplitude of [...]
Two particles P and Q start from origin and execute S.H.M along x-axis with same amplitude but with periods 3 seconds and 6 seconds respectively. The ratio of the velocities of P and Q when they are at mean position is
30
Oct
Two particles P and Q start from origin and execute S.H.M along x-axis with same amplitude but with periods 3 seconds and 6 seconds respectively. The ratio of the velocities of P and Q when they are at mean position is Time period of a particle executing SHM is 8 sec. At t=0 it is [...]
Time period of a particle executing SHM is 8 sec. At t=0 it is at the mean position. The ratio of the distance traveled by it in the 1st and the 2nd second is :
30
Oct
Time period of a particle executing SHM is 8 sec. At t=0 it is at the mean position. The ratio of the distance traveled by it in the 1st and the 2nd second is : Time period of a particle executing SHM is 8 sec. At t=0 it is at the mean position. The ratio [...]
For a simple pendulum, graph between length and time period will be a
30
Oct
For a simple pendulum, graph between length and time period will be a For a simple pendulum graph between length and time period will be a October 30, 2020 Category: Cengage NEET by C.P Singh , Chapter 13 - Simple Harmonic Motion , Part 1 ,
A particle is executing is SHM. Then the graph of velocity as a function of displacement is
30
Oct
A particle is executing is SHM. Then the graph of velocity as a function of displacement is A particle is executing is SHM. Then the graph of velocity as a function of displacement is October 30, 2020 Category: Cengage NEET by C.P Singh , Chapter 13 - Simple Harmonic Motion , Part 1 ,
A particle is executing is SHM. Then the graph of acceleration as a function of displacement is
30
Oct
A particle is executing is SHM. Then the graph of acceleration as a function of displacement is A particle is executing is SHM. Then the graph of acceleration as a function of displacement is October 30, 2020 Category: Cengage NEET by C.P Singh , Chapter 13 - Simple Harmonic Motion , Part 1 ,
The equation of SHM of a particle is d^2y/dt^2+ky=0, where k is a positive constant. The time period of motion is
30
Oct
The equation of SHM of a particle is d^2y/dt^2+ky=0, where k is a positive constant. The time period of motion is The equation of SHM of a particle is d^2y/dt^2+ky=0 where k is a positive constant. The time period of motion is October 30, 2020 Category: Cengage NEET by C.P Singh , Chapter 13 - [...]