Cengage JEE Mains Physics by B.M Sharma
A wave is represented by the equation y=7sin(7πt−0.04 pie x+3/π) where x is in meters and t is in seconds. The speed of the waves is:-
13
Sep
A wave is represented by the equation y=7sin(7πt−0.04 pie x+3/π) where x is in meters and t is in seconds. The speed of the waves is:- A wave is represented by the equation y=7sin(7πt−0.04 pie x+3/π) where x is in meters and t is in seconds. The speed of the waves is:- September 13, 2020 [...]
The equation of a transverse wave travelling on a rope is given by y=10 sin π(0.01x − 2.00t) where y and x are in cm and t in seconds. The maximum transverse speed of a particle in the rope is about.
13
Sep
The equation of a transverse wave travelling on a rope is given by y=10 sin π(0.01x − 2.00t) where y and x are in cm and t in seconds. The maximum transverse speed of a particle in the rope is about. The equation of a transverse wave travelling on a rope is given by y=10 [...]
A vertical spring carries a 5kg body and is hanging in equilibrium an additional force is applied so that the spring is further stretched. When released from this position. It performs 50 complete oscillation in 25 s, with an amplitude of 5 cm. The additional force applied is
13
Sep
A vertical spring carries a 5kg body and is hanging in equilibrium an additional force is applied so that the spring is further stretched. When released from this position. It performs 50 complete oscillation in 25 s, with an amplitude of 5 cm. The additional force applied is Figure shows the variation of force acting [...]
Figure shows the variation of force acting on a particle of mass 400 g executing simple harmonic motion. The frequency of oscillation of the particle is-
13
Sep
Figure shows the variation of force acting on a particle of mass 400 g executing simple harmonic motion. The frequency of oscillation of the particle is- Figure shows the variation of force acting on a particle of mass 400 g executing simple harmonic motion. The frequency of oscillation of the particle is- September 13, 2020 [...]
Statement 1: The value of escape velocity from the surface of earth at 30 and 60 is v1=2ve,v2=2/3ve. Statement II: The value of escape velocity is independent of angle of projection.
13
Sep
Statement 1: The value of escape velocity from the surface of earth at 30 and 60 is v1=2ve,v2=2/3ve. Statement II: The value of escape velocity is independent of angle of projection. Statement 1: The value of escape velocity from the surface of earth at 30 and 60 is v1=2ve v2=2/3ve. Statement II: The value of [...]
Statement I: The force of gravitation between a sphere and a rod of mass M2 is = (GM1M2)/r. Statement II: Newton’s law of gravitation holds correct for point masses.
13
Sep
Statement I: The force of gravitation between a sphere and a rod of mass M2 is = (GM1M2)/r. Statement II: Newton’s law of gravitation holds correct for point masses. Statement I: The force of gravitation between a sphere and a rod of mass M2 is = (GM1M2)/r. Statement II: Newton's law of gravitation holds correct [...]
Statement 1 : Kepler’s second law can be understood by conservation of angular momentum principle. Statement 2 : Kepler’s second law is related with areal velocity which can further be proved to be based on conservation of angular momentum as (dA/dt)=(r^2ω)/2.
13
Sep
Statement 1 : Kepler’s second law can be understood by conservation of angular momentum principle. Statement 2 : Kepler’s second law is related with areal velocity which can further be proved to be based on conservation of angular momentum as (dA/dt)=(r^2ω)/2. In order to shift a body of mass m from a circular orbit of [...]
Statement I: For a satellite revolving very near to the earth’s surface the time period of revolution is given by 1h24 min. Statement II: The period of revolution of a satellite depends only upon its height above the earth’s surface.
13
Sep
Statement I: For a satellite revolving very near to the earth’s surface the time period of revolution is given by 1h24 min. Statement II: The period of revolution of a satellite depends only upon its height above the earth’s surface. In order to shift a body of mass m from a circular orbit of radius [...]
Statement-1: For the planets orbiting around the sun, angular speed, linear speed, KE changes with time,but angular momentum remains constant. Statement-2: No torque is acting on the rotating planet, so its angular momentum is constant.
13
Sep
Statement-1: For the planets orbiting around the sun, angular speed, linear speed, KE changes with time,but angular momentum remains constant. Statement-2: No torque is acting on the rotating planet, so its angular momentum is constant. angular speed but angular momentum remains constant. Statement-2: No torque is acting on the rotating planet KE changes with time [...]
A planet is revolving in an elliptical orbit around the Sun. Its closest distance from the Sun is rmin and the farthest distance is rmax. If the velocity of the planet at the distance of the closest approach is ν1 and that at the farthest distance from the Sun is ν2 , then { ν1 }/{ ν2 }
13
Sep
A planet is revolving in an elliptical orbit around the Sun. Its closest distance from the Sun is rmin and the farthest distance is rmax. If the velocity of the planet at the distance of the closest approach is ν1 and that at the farthest distance from the Sun is ν2 , then { ν1 [...]