Chapter 11 – SHM
A particle executes simple harmonic motion with an amplitude of 4 cm . At the mean position the velocity of the particle is 10 cm/ s . The distance of the particle from the mean position when its speed becomes 5 cm/s is
31
Oct
A particle executes simple harmonic motion with an amplitude of 4 cm . At the mean position the velocity of the particle is 10 cm/ s . The distance of the particle from the mean position when its speed becomes 5 cm/s is A particle executing simple harmonic motion has an amplitude of 6 cm [...]
A particle executing simple harmonic motion has an amplitude of 6 cm . Its acceleration at a distance of 2 cm from the mean position is 8cms^2 The maximum speed of the particle is
31
Oct
A particle executing simple harmonic motion has an amplitude of 6 cm . Its acceleration at a distance of 2 cm from the mean position is 8cms^2 The maximum speed of the particle is A particle executing simple harmonic motion has an amplitude of 6 cm . Its acceleration at a distance of 2 cm [...]
Two simple harmonic are represented by the equation y1=0.1sin(100πt+π/3) and y2 = 0.1cosπt. The phase difference of the velocity of particle 1 with respect to the velocity of particle 2 is at time t = 0 is
31
Oct
Two simple harmonic are represented by the equation y1=0.1sin(100πt+π/3) and y2 = 0.1cosπt. The phase difference of the velocity of particle 1 with respect to the velocity of particle 2 is at time t = 0 is A particle is executing simple harmonic motion with a period of T seconds and amplitude a metre . [...]
A particle is executing simple harmonic motion with a period of T seconds and amplitude a metre . The shortest time it takes to reach a point a/2–√ from its mean position in seconds is
31
Oct
A particle is executing simple harmonic motion with a period of T seconds and amplitude a metre . The shortest time it takes to reach a point a/2–√ from its mean position in seconds is A particle is executing simple harmonic motion with a period of T seconds and amplitude a metre . The shortest [...]
The amplitude and the time period in a S.H.M. is 0.5 cm and 0.4 sec respectively. If the initial phase is π/2 radian, then the equation of S.H.M. will be
31
Oct
The amplitude and the time period in a S.H.M. is 0.5 cm and 0.4 sec respectively. If the initial phase is π/2 radian, then the equation of S.H.M. will be The amplitude and the time period in a S.H.M. is 0.5 cm and 0.4 sec respectively. If the initial phase is π/2 radian then the [...]
What is the maximum acceleration of the particle doing the SHM γ=2sin[πt/2 + ϕ] where gamma is in cm?
31
Oct
What is the maximum acceleration of the particle doing the SHM γ=2sin[πt/2 + ϕ] where gamma is in cm? What is the maximum acceleration of the particle doing the SHM γ=2sin[πt/2 + ϕ] where gamma is in cm? October 31, 2020 Category: Arihant Physics by D.C Pandey , Chapter 11 - SHM , Volume 1 [...]
Two particles are executing S.H.M. The equation of their motion are y1=10sin(ωt+π/4),y2 = 25sin(ωt+(3–√π/4)) . What is the ratio of their amplitude
31
Oct
Two particles are executing S.H.M. The equation of their motion are y1=10sin(ωt+π/4),y2 = 25sin(ωt+(3–√π/4)) . What is the ratio of their amplitude Two particles are executing S.H.M. The equation of their motion are y1=10sin(ωt+π/4) y2 = 25sin(ωt+(3–√π/4)) . What is the ratio of their amplitude October 31, 2020 Category: Arihant Physics by D.C Pandey , [...]