Chapter 11 – SHM
For any SHM, amplitude is 6cm. If instantaneous potential energy is half the total energy then distance of particle from its mean position is
31
Oct
For any SHM, amplitude is 6cm. If instantaneous potential energy is half the total energy then distance of particle from its mean position is amplitude is 6cm. If instantaneous potential energy is half the total energy then distance of particle from its mean position is For any SHM October 31, 2020 Category: Arihant Physics by [...]
In SHM for how many times potential energy is equal to kinetic energy during one complete period
31
Oct
In SHM for how many times potential energy is equal to kinetic energy during one complete period In SHM for how many times potential energy is equal to kinetic energy during one complete period October 31, 2020 Category: Arihant Physics by D.C Pandey , Chapter 11 - SHM , Volume 1 ,
A particle of mass 0.10 kg executes Simple harmonic motion with an amplitude 0.05 m and frequency 20 vib/s. Its energy of oscillation is
31
Oct
A particle of mass 0.10 kg executes Simple harmonic motion with an amplitude 0.05 m and frequency 20 vib/s. Its energy of oscillation is A particle of mass 0.10 kg executes Simple harmonic motion with an amplitude 0.05 m and frequency 20 vib/s. Its energy of oscillation is October 31, 2020 Category: Arihant Physics by [...]
A body is executing simple harmonic motion with an angular frequency 2 rad/s. The velocity of the body at 20 mm displacement, when the amplitude of motion is 60 mm, is
31
Oct
A body is executing simple harmonic motion with an angular frequency 2 rad/s. The velocity of the body at 20 mm displacement, when the amplitude of motion is 60 mm, is A body is executing simple harmonic motion with an angular frequency 2 rad/s. The velocity of the body at 20 mm displacement is when [...]
The motion of a particle executing S.H.M. is given by x=0.01sin100π( t + 0.05) ,The time period is
31
Oct
The motion of a particle executing S.H.M. is given by x=0.01sin100π( t + 0.05) ,The time period is The motion of a particle executing S.H.M. is given by x=0.01sin100π( t + 0.05) The time period is October 31, 2020 Category: Arihant Physics by D.C Pandey , Chapter 11 - SHM , Volume 1 ,
The displacement of a particle executing SHM is given by y=0.25 sin 200t cm. Calculate the maximum speed of the particle.
31
Oct
The displacement of a particle executing SHM is given by y=0.25 sin 200t cm. Calculate the maximum speed of the particle. The displacement of a particle executing SHM is given by y=0.25 sin 200t cm. Calculate the maximum speed of the particle. October 31, 2020 Category: Arihant Physics by D.C Pandey , Chapter 11 - [...]
If the maximum acceleration of the body executing S.H.M. is a0 and maximum velocity is V0. The amplitude is given by
31
Oct
If the maximum acceleration of the body executing S.H.M. is a0 and maximum velocity is V0. The amplitude is given by If the maximum acceleration of the body executing S.H.M. is a0 and maximum velocity is V0. The amplitude is given by October 31, 2020 Category: Arihant Physics by D.C Pandey , Chapter 11 - [...]
A body is vibrating in simple harmonic motion . If its acceleration in 12cms^−2 at a displacement 3 cm from the mean position, then time period is
31
Oct
A body is vibrating in simple harmonic motion . If its acceleration in 12cms^−2 at a displacement 3 cm from the mean position, then time period is A body is vibrating in simple harmonic motion . If its acceleration in 12cms^−2 at a displacement 3 cm from the mean position then time period is October [...]
Velocity at mean position of a particle executing SHM is v. Velocity of the particle at a distance equal to half of the amplitude will be
31
Oct
Velocity at mean position of a particle executing SHM is v. Velocity of the particle at a distance equal to half of the amplitude will be Velocity at mean position of a particle executing SHM is v. Velocity of the particle at a distance equal to half of the amplitude will be October 31, 2020 [...]
The maximum velocity of a simple harmonic motion represented by y=3sin(100t+π/6) is given by
31
Oct
The maximum velocity of a simple harmonic motion represented by y=3sin(100t+π/6) is given by The maximum velocity of a simple harmonic motion represented by y=3sin(100t+π/6) is given by October 31, 2020 Category: Arihant Physics by D.C Pandey , Chapter 11 - SHM , Volume 1 ,