Chapter 11 – SHM
A simple pendulum 4 m long swing with an amplitude of 0.2m. What is its acceleration at the ends of its path?
26
Jun
A simple pendulum 4 m long swing with an amplitude of 0.2m. What is its acceleration at the ends of its path? A simple pendulum 4 m long swing with an amplitude of 0.2m. What is its acceleration at the ends of its path? June 26, 2021 Category: Arihant Physics by D.C Pandey , Chapter [...]
A ball of mass 2 kg hanging from a spring oscillates with a time period 2pi seconds. Ball is removed when it is in equilibrium position, then spring shortens by
26
Jun
A ball of mass 2 kg hanging from a spring oscillates with a time period 2pi seconds. Ball is removed when it is in equilibrium position, then spring shortens by A ball of mass 2 kg hanging from a spring oscillates with a time period 2pi seconds. Ball is removed when it is in equilibrium [...]
A particle is subjected to two simple harmonic motion in the same direction having equal amplitudes and equal frequency. If the resultant amplitude is equal to the amplitude of the individual motions. Find the phase difference between the individual motions.
26
Jun
A particle is subjected to two simple harmonic motion in the same direction having equal amplitudes and equal frequency. If the resultant amplitude is equal to the amplitude of the individual motions. Find the phase difference between the individual motions. Acceleration displacement graph of a particle executing S.H.M is as shown in given figure. The [...]
Let T1 and T2 be the time periods of two springs A and B when a mass m is suspended from them separately. Now both the springs are connected in parallel and same mass m is suspended with them. Now let T be the time period in this position. Then
26
Jun
Let T1 and T2 be the time periods of two springs A and B when a mass m is suspended from them separately. Now both the springs are connected in parallel and same mass m is suspended with them. Now let T be the time period in this position. Then Acceleration displacement graph of a [...]
A wire of length l , area of cross section A and young’s modules of elasticity y is suspended from the roof of a building. A block of mass m is attached at lower end of the wire. if the block is displaced from its mean position and then released the block starts oscillating. Time period of these oscillation will be
26
Jun
A wire of length l , area of cross section A and young’s modules of elasticity y is suspended from the roof of a building. A block of mass m is attached at lower end of the wire. if the block is displaced from its mean position and then released the block starts oscillating. Time [...]
The potential energy of a simple harmonic oscillator of mass 2 kg in its mean position is 5J. If its total energy is 9J and its amplitude is 0.01 m, its time period would be
26
Jun
The potential energy of a simple harmonic oscillator of mass 2 kg in its mean position is 5J. If its total energy is 9J and its amplitude is 0.01 m, its time period would be its time period would be The potential energy of a simple harmonic oscillator of mass 2 kg in its mean [...]
An object suspended from a spring exhibits oscillations of period T. Now the spring is cut in two halves and the same object is suspended with two halves as shown in figure. The new time period of oscillation will become
26
Jun
An object suspended from a spring exhibits oscillations of period T. Now the spring is cut in two halves and the same object is suspended with two halves as shown in figure. The new time period of oscillation will become Acceleration displacement graph of a particle executing S.H.M is as shown in given figure. The [...]
A block of mass m is suspended by different springs of force constant shown in figure. Let time period of oscillation in these four positions be T1, T2, T3 and T4 . Then :
26
Jun
A block of mass m is suspended by different springs of force constant shown in figure. Let time period of oscillation in these four positions be T1, T2, T3 and T4 . Then : A block of mass m is suspended by different springs of force constant shown in figure. Let time period of oscillation [...]
Displacement-time equation of a particle executing SHM is x=A sin (omega t+(pi)/6) Time taken by the particle to go directly from x=-A/2 to x=+A/2 is
26
Jun
Displacement-time equation of a particle executing SHM is x=A sin (omega t+(pi)/6) Time taken by the particle to go directly from x=-A/2 to x=+A/2 is Displacement-time equation of a particle executing SHM is x=A sin (omega t+(pi)/6) Time taken by the particle to go directly from x=-A/2 to x=+A/2 is June 26, 2021 Category: Arihant [...]
A particle of mass 0.1 kg executes SHM under a force F=(−10x)N. Speed of particle at mean position is 6m/s. Then amplitude of oscillations is.
26
Jun
A particle of mass 0.1 kg executes SHM under a force F=(−10x)N. Speed of particle at mean position is 6m/s. Then amplitude of oscillations is. A particle of mass 0.1 kg executes SHM under a force F=(−10x)N. Speed of particle at mean position is 6m/s. Then amplitude of oscillations is. June 26, 2021 Category: Arihant [...]