zX^M + 2 He ^4 gives 15P^30 + 0n^1 . Then (a) Z = 12 , M = 27 (b) Z = 13 , M = 27 (c) Z = 12 , M = 17 (d) Z = 13 , M = 28 M = 17 (d) Z = 13 M = 27 (b) Z = 13 M = 27 (c) Z = 12 M = 28 zX^M + 2 He ^4 gives 15P^30 + 0n^1 . Then (a) Z = 12 February 13, 2021 Category: Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) , Facebook Messenger WhatsApp Share this:TwitterFacebook Related
