You are given vectors A = 5i – 6.5j and B = 10i – 7j. A third vector C lies in the x-y plane. Vector C is perpendicular to vector A and the scalar product of C with B is 15 You are given vectors A = 5i - 6.5j and B = 10i - 7j. A third vector C lies in the x-y plane. Vector C is perpendicular to vector A and the scalar product of C with B is 15 September 16, 2020 Category: Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) , Facebook Messenger WhatsApp Share this:TwitterFacebook Related