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Sahay Sir > Question Answers > JEE Mains Physics 2002-2019 Solved Video Solutions > Practice Set 1 > You are given that Mass of 7 3 Li = 7.0160 u, Mass of 4 2 He = 4.0026 u, and Mass of 1 1 H = 1.0079 u. When 20 g of 7 3 Li is converted into 24 He by proton capture, the energy liberated, (in kWh), is [Mass of nucleon = 1 GeV/c^2]

You are given that Mass of 7 3 Li = 7.0160 u, Mass of 4 2 He = 4.0026 u, and Mass of 1 1 H = 1.0079 u. When 20 g of 7 3 Li is converted into 24 He by proton capture, the energy liberated, (in kWh), is [Mass of nucleon = 1 GeV/c^2]

(in kWh) and Mass of 1 1 H = 1.0079 u. When 20 g of 7 3 Li is converted into 24 He by proton capture is [Mass of nucleon = 1 GeV/c^2] Mass of 4 2 He = 4.0026 u the energy liberated You are given that Mass of 7 3 Li = 7.0160 u