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Sahay Sir > Question Answers > Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) > x1 = 3 sin omega t; x2 = 4 cos omega t Find (a) amplitude of resultant SHM, (b) equation of the resultant SHM.

x1 = 3 sin omega t; x2 = 4 cos omega t Find (a) amplitude of resultant SHM, (b) equation of the resultant SHM.

October 30, 2020
Category: Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) ,

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