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Sahay Sir > Question Answers > Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) > When two progressive waves y1 = 4 sin (2x – 6t) and y2 = 3 sin (2x – 6t – pie/2) superimposed, the amplitude of the resultant wave is

When two progressive waves y1 = 4 sin (2x – 6t) and y2 = 3 sin (2x – 6t – pie/2) superimposed, the amplitude of the resultant wave is

the amplitude of the resultant wave is When two progressive waves y1 = 4 sin (2x - 6t) and y2 = 3 sin (2x - 6t - pie/2) superimposed