When one litre of a saturated solution of PbCl2 (molecular weight =278 g/mol) is evaporated, the residue is found to weigh 2.78 g. If Ksp of PbCl2 is represented as y×10^−6 , then find the value of y. the residue is found to weigh 2.78 g. If Ksp of PbCl2 is represented as y×10^−6 then find the value of y. When one litre of a saturated solution of PbCl2 (molecular weight =278 g/mol) is evaporated November 18, 2020 Category: Chapter 6 - Ionic Equilibrium (Level 1 and Level 2) , Chapter 7 - Equilibrium , N Awasthi Physical Chemistry , Facebook Messenger WhatsApp Share this:TwitterFacebook Related