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Sahay Sir > Question Answers > Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) > When CH2 = CH – COOH is reduced with LiAlH4, the compound obtained will be (a) CH3 – CH2 – COOH (b) CH2 = CH – CH2OH (c) CH3 – CH2 – CH2OH (d) CH3 – CH2 – CHO

When CH2 = CH – COOH is reduced with LiAlH4, the compound obtained will be (a) CH3 – CH2 – COOH (b) CH2 = CH – CH2OH (c) CH3 – CH2 – CH2OH (d) CH3 – CH2 – CHO

the compound obtained will be (a) CH3 - CH2 - COOH (b) CH2 = CH - CH2OH (c) CH3 - CH2 - CH2OH (d) CH3 - CH2 - CHO When CH2 = CH - COOH is reduced with LiAlH4