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Sahay Sir > Question Answers > JEE Mains Physics 2002-2019 Solved Video Solutions > Practice Set 1 > When a particle of mass m is attached to a vertical spring of spring constant k and released, its motion is described by y(t) = y0sin^2ωt, where ‘y’ is measured from the lower end of unstretched spring. Then ω is

When a particle of mass m is attached to a vertical spring of spring constant k and released, its motion is described by y(t) = y0sin^2ωt, where ‘y’ is measured from the lower end of unstretched spring. Then ω is

its motion is described by y(t) = y0sin^2ωt When a particle of mass m is attached to a vertical spring of spring constant k and released where ‘y’ is measured from the lower end of unstretched spring. Then ω is