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Sahay Sir > Question Answers > Cengage NEET by C.P Singh > Part 1 > Chapter 14 - Fluid Mechanics > We have two (narrow) capillary tubes T1 and T2 . Their lengths are l1 and l2 and radii of cross-section are r1 and r2 respectively. The rate of flow of water under a pressure difference P through tube T1 is 8cm^3/sec. If l1=2l2 and r1=r2 what will be the rate of flow when the two tubes are connected in series and pressure difference across the combination is same as before (=P)

We have two (narrow) capillary tubes T1 and T2 . Their lengths are l1 and l2 and radii of cross-section are r1 and r2 respectively. The rate of flow of water under a pressure difference P through tube T1 is 8cm^3/sec. If l1=2l2 and r1=r2 what will be the rate of flow when the two tubes are connected in series and pressure difference across the combination is same as before (=P)

3 different shapes are gives. Identify the combination of air resistances which truly represents the physical situation. (the cross sectional areas are the same). the resistance of air depends to a great extent on the shape of the body When a body falls in air