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Sahay Sir > Question Answers > Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) > Vapour presuure of pure ‘ A’ is 70 mm of Hg at 25 degree C . it forms an ideal solution with ‘ B’ in which which mole fraction of A is 0.8 . If the vapour pressure of the solution of pure ‘ B’ at 25 degree C is

Vapour presuure of pure ‘ A’ is 70 mm of Hg at 25 degree C . it forms an ideal solution with ‘ B’ in which which mole fraction of A is 0.8 . If the vapour pressure of the solution of pure ‘ B’ at 25 degree C is

At 80∘ C the amount of A in the mixture is : (1 atm=760 mm Hg) the vapour pressure of pure liquid A is 520 mm Hg and that of pure liquid B is 1000 mm Hg. If a mixture solution of A and B boils at 80∘ C and 1 atm pressure