Vapour pressure of CCl 4 at 25 o C is 143 mm of Hg. 0.5 g of a non-volatile solute (mol. Mass =65) is dissolved in 100 mL CCl4 . Find the vapour pressure of the solution: (Density of CCl 4 = 1.58 g/cm 3 ) For 0.1 M solution the colligative property will follow the order (a) NaCL > Na2SO4 > Na3PO4 (b) NaCL < Na2SO4 < Na3PO4 December 12, 2020 Category: Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) , Facebook Messenger WhatsApp Share this:TwitterFacebook Related