Unpolarized light of intensity 32 W m^-2 passes through three polarizers such that the transmission axis of the last polarizer is crossed with the first. If the intensity of the emerging light is 3 W m^-2, lemda 1 = 589 nm and lemda 2 = 589.6 nm. As the path difference increases Sodium light has two wavelengths when is the visibility of the fringes a minimum? September 10, 2020 Category: Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) , Facebook Messenger WhatsApp Share this:TwitterFacebook Related