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Sahay Sir > Question Answers > Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) > Two resistance R1 = 50 ohm and R2 = 40 ohmA are connected with a battery of emf 5 V and internal resistance 20 ohm as shown in fig, A voltmerter of resistance 1000 ohm is used to measurev the potential difference across R. Find the percentage error made in the reading.

Two resistance R1 = 50 ohm and R2 = 40 ohmA are connected with a battery of emf 5 V and internal resistance 20 ohm as shown in fig, A voltmerter of resistance 1000 ohm is used to measurev the potential difference across R. Find the percentage error made in the reading.

A voltmerter of resistance 1000 ohm is used to measurev the potential difference across R. Find the percentage error made in the reading. Two resistance R1 = 50 ohm and R2 = 40 ohmA are connected with a battery of emf 5 V and internal resistance 20 ohm as shown in fig