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Sahay Sir > Question Answers > Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) > Two radioactive materials A and B decay constant 3 lemda and 2 lemda respectively. At t = 0, the numbers of nuclei of A and B are 4 N0 and 2N0 respectively, then

Two radioactive materials A and B decay constant 3 lemda and 2 lemda respectively. At t = 0, the numbers of nuclei of A and B are 4 N0 and 2N0 respectively, then

the numbers of nuclei of A and B are 4 N0 and 2N0 respectively then Two radioactive materials A and B decay constant 3 lemda and 2 lemda respectively. At t = 0