Two point charges 100 μC and 5 μC are placed at points A and B respectively with AB = 40 cm. The work done by external force in displacing the charge 5 μC from B to C, where BC = 30 cm, angle ABC = π^2 and 1 / 4πε0 = 9 × 10^9 Nm^2/ C2 angle ABC = π^2 and 1 / 4πε0 = 9 × 10^9 Nm^2/ C2 Two point charges 100 μC and 5 μC are placed at points A and B respectively with AB = 40 cm. The work done by external force in displacing the charge 5 μC from B to C where BC = 30 cm September 17, 2020 Category: Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) , Facebook Messenger WhatsApp Share this:TwitterFacebook Related