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Sahay Sir > Question Answers > Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) > Two particles ‘A’ and ‘B’ start SHM at t = 0. Their positions as function of time are given by XA = A sin omega t XB = A sin (omega t + pie/3)

Two particles ‘A’ and ‘B’ start SHM at t = 0. Their positions as function of time are given by XA = A sin omega t XB = A sin (omega t + pie/3)

Two particles 'A' and 'B' start SHM at t = 0. Their positions as function of time are given by XA = A sin omega t XB = A sin (omega t + pie/3)