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Sahay Sir > Question Answers > Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) > Two particles A and B execute simple harmonic motion according to the equations y1 = 3 sin omega t and y2 = 4 sin (omega t + (pie/2)) + 3 sin omega t. Find the phase difference between them.

Two particles A and B execute simple harmonic motion according to the equations y1 = 3 sin omega t and y2 = 4 sin (omega t + (pie/2)) + 3 sin omega t. Find the phase difference between them.

Two particles A and B execute simple harmonic motion according to the equations y1 = 3 sin omega t and y2 = 4 sin (omega t + (pie/2)) + 3 sin omega t. Find the phase difference between them.