Two equally charged identical metal spheres A and B repel each other with a force of 3×10^−5 N. Another identical uncharged sphere C is touched with A and then placed at the midpoint between A and B. Net force on C is. Force between two identical charges placed at a distance of r in vacuum is F. Now a slab of dielectric constant K = 4 is inserted between these two charges . If the thickness of the slab is r/2 then the force between the charges will becomes November 30, 2020 Category: Cengage JEE Mains Physics by B.M Sharma , Chapter 17 - Electric Charge and Field , Facebook Messenger WhatsApp Share this:TwitterFacebook Related