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Sahay Sir > Question Answers > Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) > To the right of line PQ is a uniform magnetic field B. B1A is the line of incidence of a charged particle, which comes out of the field along DE ; CA and DF are the normals at A and D. B1AC = theta . Angle measured from CA in clockwise direction is taken as positive . what will be the value of theta so that angle subtented by the part of the circle ( along which charged particles moves in the field ) at its centre and facing the circle is less than pie?

To the right of line PQ is a uniform magnetic field B. B1A is the line of incidence of a charged particle, which comes out of the field along DE ; CA and DF are the normals at A and D. B1AC = theta . Angle measured from CA in clockwise direction is taken as positive . what will be the value of theta so that angle subtented by the part of the circle ( along which charged particles moves in the field ) at its centre and facing the circle is less than pie?

0) is placed in x−y plane as shown in figure. The force on semicircular wire will be 2 A uniform magnetic field B =(3 i ^ +4 j ^ ​ + k ^ ) exists in region of space. A semicircular wire of radius 1 m carrying current 1 A having its centre at (2 To the right of line PQ is a uniform magnetic field B. B1A is the line of incidence of a charged particle Two rectangular plates A and B placed at a distance 2a apart