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Sahay Sir > Question Answers > Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) > To generate power of 3.2 megawatt , the number of fissions of U^235 per minute is ( Energy released per fission = 200 Me V, 1 eV = 1.6 X 10^-19 J )

To generate power of 3.2 megawatt , the number of fissions of U^235 per minute is ( Energy released per fission = 200 Me V, 1 eV = 1.6 X 10^-19 J )

1 eV = 1.6 X 10^-19 J ) the number of fissions of U^235 per minute is ( Energy released per fission = 200 Me V To generate power of 3.2 megawatt