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Sahay Sir > Question Answers > Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) > Three distinct current carrying wires intersect a finite rectangular plane ABCD. The current in left wire and the loop is I1. The direction of current in left most wire and right most loop is downwards as shown in figure. The current I2 through middle wire is adjusted so that the path integral of the total magnetic field along the perimeter of the rectangle is zero, that is, ∮ABCD AB .dl =0. Then the current I2 is-

Three distinct current carrying wires intersect a finite rectangular plane ABCD. The current in left wire and the loop is I1. The direction of current in left most wire and right most loop is downwards as shown in figure. The current I2 through middle wire is adjusted so that the path integral of the total magnetic field along the perimeter of the rectangle is zero, that is, ∮ABCD AB .dl =0. Then the current I2 is-

Figure shows two closed paths wrapped around two conducting loops carrying currents i1=5.0 A and i2 ​=3.0 A. What is the value of the integral ∮ B.d s for (a) path 1 and (b) path 2?