Three constant forces F1 = 2i-3j+2k, F2 = i+j-k, and F3 = 3i+j-2k in newtons displace a particle from (1, -1, 2) to (-1, -1, 3) and then to 1 2) to (-1 3) and then to and F3 = 3i+j-2k in newtons displace a particle from (1 F2 = i+j-k Three constant forces F1 = 2i-3j+2k August 30, 2020 Category: Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) , Facebook Messenger WhatsApp Share this:TwitterFacebook Related