The (x – t) graph of a particle undergoing simple harmonic motion is shown below. The acceleration of the particle at t=4/3 s is A particle executes SHM with a time period of 16s. At time t=2s its velocity is 4 ms^−1. The amplitude of motion in metre is? the particle crosses the mean position while at t=4s November 5, 2020 Category: Cengage NEET by C.P Singh , Chapter 13 - Simple Harmonic Motion , Part 1 , Facebook Messenger WhatsApp Share this:TwitterFacebook Related