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Sahay Sir > Question Answers > JEE Mains Physics 2002-2019 Solved Video Solutions > Chapter 8 - Thermodynamics > The work of 146 kJ is performed in order to compress one kilo mole of a gas adiabatically and in this process, the temperature of the gas increases by 7°C. The gas is (R = 8.3 J mol^-1 K^-1)

The work of 146 kJ is performed in order to compress one kilo mole of a gas adiabatically and in this process, the temperature of the gas increases by 7°C. The gas is (R = 8.3 J mol^-1 K^-1)

the temperature of the gas increases by 7°C. The gas is (R = 8.3 J mol^-1 K^-1) The work of 146 kJ is performed in order to compress one kilo mole of a gas adiabatically and in this process