Question Answers

Sahay Sir > Question Answers > JEE Mains Physics 2002-2019 Solved Video Solutions > Practice Set 1 > The work done by a gas molecule in an isolated system is given by, W = ab^2e^-x^2/akT , where x is the displacement, k is the Boltzmann constant and T is the temperature, α and β are constants. Then the dimension of β will be :

The work done by a gas molecule in an isolated system is given by, W = ab^2e^-x^2/akT , where x is the displacement, k is the Boltzmann constant and T is the temperature, α and β are constants. Then the dimension of β will be :

k is the Boltzmann constant and T is the temperature The work done by a gas molecule in an isolated system is given by W = ab^2e^-x^2/akT where x is the displacement α and β are constants. Then the dimension of β will be :