The water drops fall at regular intervals from a tap 5 m above the ground. The third drop is leaving the tap at the instant the first touches the ground. How far above the ground is the second drop at that instant? A particle moves along a straight line such that its displacement s at any time t is given by s = 3t^3+ 7t^2+ 14t + 5. The acceleration of the particle at t = 1 s is August 23, 2020 Category: Chapter 2 - Vectors , Chapter 3 - Motion in a Straight Line , NEET Last 32 Years Solved 1988 - 2019 Physics and Chemistry Video Solutions , Physics , Facebook Messenger WhatsApp Share this:TwitterFacebook Related