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Sahay Sir > Question Answers > NCERT Class 10 > Maths > Chapter 7 - Coordinate Geometry > The vertices of triangle ABC are A (4, 6), B (1, 5) and C (7, 2). A line is drawn to intersect sides AB and AC at D and E respectively ,such that AB/AD = AC/AE = 4/1. Calculate the area of the △ADE and compare it with the area △ABC ?

The vertices of triangle ABC are A (4, 6), B (1, 5) and C (7, 2). A line is drawn to intersect sides AB and AC at D and E respectively ,such that AB/AD = AC/AE = 4/1. Calculate the area of the △ADE and compare it with the area △ABC ?

October 5, 2020
Category: Chapter 7 - Coordinate Geometry , Maths , NCERT Class 10 ,

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The vertices of triangle ABC are A (4, 6), B (1, 5) and C (7, 2). A line is drawn to intersect sides AB and AC at D and E respectively ,such that AB/AD = AC/AE = 4/1​. Calculate the area of the △ADE and compare it with the area △ABC ?

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The vertices of triangle ABC are A (4, 6), B (1, 5) and C (7, 2). A line is drawn to intersect sides AB and AC at D and E respectively ,such that AB/AD = AC/AE = 4/1. Calculate the area of the △ADE and compare it with the area △ABC ?