The value of (tan1° tan2° tan3° … tan89°) is The value of (tan1° tan2° tan3° … tan89°) is November 25, 2020 Category: Chapter 8 - Introduction to Trigonometry , Maths , NCERT Class 10 , Facebook Messenger WhatsApp Share this:TwitterFacebook Related Choose the correct option. Justify your choice. (i) 9 sec^2 A - 9 tan^2 A =If 3 cot A = 4, check whether 1-tan^2 A/1+tan^2 A=cos^2 A -sin^2 A or not.Choose the correct option and justify your choice: (iv) 2 tan 30°/1 - tan^2 30° =
